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3 years ago

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In September, a website had 11,513 visitors. In October, the website had 23,190 more visitors than it did in September. The webs

ite had the same number of visitors in November as it did in October. How many visitors did the website have in September, October, and November combined?

1 answer:

rjkz [21]3 years ago

7 0

Answer:

80,913

Step-by-step explanation:

11,513 September

+ 23,190 for for October which would be 34,703 for October plus another 34,703 for November. That total is 80,913

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Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

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$\displaystyle z = \frac{5 - \mu}{2}$ .

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Solve the equation $\displaystyle z = \frac{x - \mu}{\sigma}$ for the mean, $\mu$ :

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Answer:

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