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3 years ago

Help please I don't understand. this is on my homework but it's due tomorrow

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

Measure of PQB is 15.4 because QB bisects PQR into 2 equal angles and measure of PQR is 2(15.4)=30.8

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At breakfast, a restaurant charges $2 for the first cup of orange juice and then $1 for each refill. Which graph represents this

Black_prince [1.1K]

Graph 4 represents the situation

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4 years ago

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What is the slope of a horizontal line

Step2247 [10]

Answer:

Step-by-step explanation:

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3 years ago

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Which phrase describes the algebraic expression 6x?

topjm [15]

Answer:

The product of 6 and a number

Step-by-step explanation:

There isn't any "real" mathematics needed to find the answer, just common background knowledge:

6x = 6 times x,

and product is referencing multiplication

(Since quotient is for division, difference for subtraction, and sum for addition)

considering we need to represent an expression which uses multiplication in words, the correct answer is:

O the product of 6 and a number

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2 years ago

Which equation is true? I. (32 ÷ 8 – 2)6 = (32 – 1)2 II. 72 ÷ 9·4 = 62 ÷ (6 + 3) II only Neither I nor II I only I and II

Umnica [9.8K]

Answer: The answer is (b) Neither I nor II.

Step-by-step explanation: We are given two equations and we need to find which is true. Since it is a simple algebraic question, so we just need to follow BODMAS rule to check the equations.

The equations are as follows -

$(I)~~L.H.S=(\dfrac{32}{8}-2)6=(4-2)6=2\times 6=12.$

$R.H.S=(32-1)2=31\times 2=62.$

Since L.H.S ≠ R.H.S, so this equation is not correct.

$(II)~~L.H.S=\dfrac{72}{9\times 4}=2.$

$R.H.S=\dfrac{62}{6+3}=\dfrac{62}{9}.$

Since L.H.S ≠ R.H.S, so this equation is also not correct.

Thus, the correct option is (b) Neither I nor II.

4 0

3 years ago

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If tan a = 9／40<br>use trigonometric identities to find the values of sin a and cos a.

Sindrei [870]

Answer:

see explanation

Step-by-step explanation:

Given

tan a = $\frac{9}{40}$ = $\frac{opposite}{adjacent}$

We require the hypotenuse h

Using Pythagoras' identity

h² = 9² + 40² = 81 + 1600 = 1681 ( take square root of both sides )

h = $\sqrt{1681}$ = 41 , thus

sin a = $\frac{opposite}{hypotenuse}$ = $\frac{9}{41}$

cos a = $\frac{adjacent}{hypotenuse}$ = $\frac{40}{41}$

4 0

3 years ago