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evablogger [386]
3 years ago
5

What equation results from completing the square and then factoring?

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

\large\boxed{D.\ (x-4)^2=55}

Step-by-step explanation:

(a-b)^2=a^2-2ab+b^2\qquad(*)\\\\\\x^2-8x=39\\\\x^2-2(x)(4)=39\qquad\text{add}\ 4^2=16\ \text{to both sides}\\\\\underbrace{x^2-2(x)(4)+4^2}_{(*)}=39+16\\\\(x-4)^2=55

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Gabe saved $113. This amount was at least $19 more than his brother saved. How much money did Gabe's brother save?
baherus [9]
Gabe's brother saved $94
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3 years ago
37. Three married couples have purchased tickets for a play. Spouses are to be seated next to each other, and the six seats are
Maurinko [17]

48

1st seat 6 possible for each 6 only 1 possible(spouse) for seat 2

3rd seat 4 possible for each 4 only 1 possible(spouse) for seat 4

5th seat 2 possible for each 2 only 1 possible(spouse) for seat 6

6 x 4 x 2 = 48

OR 3 couples possible arrangements 3 x 2 x1 = 6

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6 0
3 years ago
Los puntos de intersección de los gráficos de f(x)=x2+6x−7 y g(x)=4x−10
alisha [4.7K]

Answer:

Those graphs do not intersect.

Estes gráficos no se intersecciónan

Step-by-step explanation:

The intersection points are x for which:

f(x) = g(x)

In this question:

f(x) = x^{2} + 6x - 7

g(x) = 4x - 10

So

x^{2} + 6x - 7 = 4x - 10

x^{2} + 2x + 3 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

x^{2} + 2x + 3 = 0

So a = 1, b = 2, c = 3

\bigtriangleup = b^{2} - 4ac = 2^{2} - 4*1*3 = -8

Sincce \bigtriangleup is negative, there are no solutions, which means that those graphs do not intersect.

7 0
3 years ago
What is y+2= (-3) (x-4)
TEA [102]
Y=-3x+10 is your awnser
3 0
2 years ago
Read 2 more answers
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