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3 years ago

What is the value of the expression below when y = 8 and z = 9? 5y – 2z

Mathematics

1 answer:

Natalka [10]3 years ago

3 0

Answer:

$\boxed {\tt 22}$

Step-by-step explanation:

We are given the expression:

$5y-2z$

We want to find the value of the expression when y=8 and z=9. Therefore, we must substitute 8 in for y and 9 in for z.

$5(8)-2(9)$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Multiply 5 and 8.

$40-2(9)$

Multiply 2 and 9.

$40-18$

Subtract 18 from 40.

$22$

The value of the expression 5y-2z at y=8 and z=9 is 22.

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find the slope of the line passing through each pair of points. if the slope is undefined, write undefined. (5,9) and (5,-3)

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Answer:

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Step-by-step explanation:

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3 years ago

Two sides of a triangle measure 8 cm and 15 cm. Whi[:h could be the length of the third side?

lutik1710 [3]

18 cm is correct .

Step-by-step explanation:

The sum of two smaller sides is greater that the largest side.

It is given that the two sides of a triangle measure 8 cm and 15 cm.

Case 1: Let 8 cm and 15 cm. are smaller side. So,

Third side < 8 + 15

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It means 3rd side must be less than 23

Case 2: Let 15 cm is the largest side.

15 < Third side + 8

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Since only 18 is less than 23 and greater than 7, therefore the possible length of third sides is 18 cm and option 2 is correct.

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3 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

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The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

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$- 0.0265\le K \le 0.0465$

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3 years ago

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