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3 years ago

QUICK HELP!! Will give brainliest!! Thank you

Mathematics

2 answers:

user100 [1]3 years ago

6 0

3 is the y-intercept

and -6 is the x-intercept

usually they don't have y behind the y-intercept so usually its the one that doesn't have x, they usually only put x.

Nadya [2.5K]3 years ago

4 0

The correct answer to this equation is X-inter=(-3.15,0) and Y-inter=(0,6.3) and heres why:

To solve this problem we must isolate the y-variable and then graph. Here are the steps to do that

$-6x+3y=18.9$ Now add 6x to both sides to get:

$3y=18.9+6x$ Next we divide both sides by the 3 next to the "y" to get: $y=\frac{18.9+6x}{3}\\$

Then you can simply graph this new equation to find your points. There is also another way to do it without graphing but it will take a lot more explaining and this way is faster.

If you find out that my answer is wrong, please tell me and I promise I will come back and rework my math. Thanks :)

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A Carpenter who is installing cabinets uses thin pieces of material called shims to fill gaps. the carpenter uses four shims to

daser333 [38]

Answer: .235

Step-by-step explanation:

Total Distance - Shim 1 - Shim 2 - Shim 3 = Shim4

1.2 cm - 0.75 cm - 0.125 - 0.09 cm = 0.235 cm

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2 years ago

lunch period a 26 out of 52 ate turkey sandwiches. lunch period b 21 out of 49 ate turkey sandwiches. which period had a greater

Gwar [14]

26/52 because reducing like terms gives us half compared to 21/49 being way less than half based on adding the numerators of these 2 fractions.

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2 years ago

The random variable X has the following probability density function: fX(x) = ( xe−x , if x > 0 0, otherwise. (a) Find the mo

dusya [7]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given value:

$\to f_X (x) \ \ xe^{-x} \ , \ x>0$

For point a:

Moment generating function of X=?

Using formula:

$\to M(t) =E(e^{tx})= \int^{\infty}_{-\infty} \ e^{tx} f(x) \ dx$

$M(t) = \int^{\infty}_{-\infty} \ e^{tx}xe^{-x} \ dx = \int^{\infty}_{0} \ xe^{(t-1)x} \ dx$

integrating the values by parts:

$u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0} -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\$

$= \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\$

Therefore, the moment value generating by the function is $=\frac{1}{(t-1)^2}$

In point b:

$E(X^n)=?$

Using formula: $E(X^n)= M^{n}_{X}(0)$

form point (a):

$\to M_{X}(t)=\frac{1}{(t-1)^2}$

Differentiating the value with respect of t

$M'_{X}(t)=\frac{-2}{(t-1)^3}$

when $t=0$

$M'_{X}(0)=\frac{-2}{(0-1)^3}= \frac{-2}{(-1)^3}= \frac{-2}{-1}=2\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M'''_{X}(t)=\frac{(-2)(-3)(-4)}{(t-1)^5}\\\\M''_{X}(0)=\frac{(-2)(-3)(-4)}{(0-1)^5}= \frac{24}{(-1)^5}= \frac{24}{-1}=-24\\\\\therefore \\\\M^{K}_{X} (t)=\frac{(-2)(-3)(-4).....(k+1)}{(t-1)^{k+2}}\\\\$

$M^{K}_{X} (0)=\frac{(-2)(-3)(-4).....(k+1)}{(-1)^{k+2}}\\\\\therefore\\\\E(X^n) = \frac{(-2)(-3)(-4).....(n+1)}{(-1)^{n+2}}\\\\$

7 0

2 years ago

Adam put $100 in a savings account. After 10 years, he had $1649 in the

Leno4ka [110]

Step-by-step explanation:

hihi, so this is a classic interest rate problem. It's not too bad if you know your properties of e and ln. After establishing the base equation you can divide by 100 then take the natural log of both sides to "get rid" of the e and finally end it by dividing by 10 to isolate r.

4 0

3 years ago

A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the

Alexxx [7]

For palarell lines, slope are equal.
slope of first line = (y2 - y1)/(x2 - x1) = (-7 - 9)/(-12 - 8) = -16/-20 = 4/5
equation of a line passing through a point is given by: y - y1 = m(x - x1); where (x1, y1) = (-5, -15) and m = 4/5.
Therefore equation of the line is y - (-15) = 4/5(x - (-5))
y + 15 = 4/5(x + 5)

7 0

3 years ago

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