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Rasek [7]
3 years ago
14

3. Find the product of 25x^2y and -6x²y3

Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

-150 (x^2y+2)y³

Step-by-step explanation:

To Find the product of 25x^2y and -6x²y3.

(25x^2y) (-6x²y³)

= 25(-6) (x^2y+2) y³

= -150 (x^2y+2)y³

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Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
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Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
2 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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