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abruzzese [7]
3 years ago
7

jen picked 3/4 of a gallon of strawberries in a half of hour .if she keeps picking strawberries at the same rate.how many gallon

s will she have picked in 2 hours
Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0
3 gallons of strawberries. 

3/4 * 4/1 = 12/4 = 3 

or you can use the butterfly method on the fours and get 

3/1 * 1/1 = 3 
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uhammad, a shipping and receiving clerk, uses 1 yard, 2 feet, 4 inches of twine to wrap each carton he packs. He has to pack 29
irina1246 [14]

Answer

Find out the how much twine will he needs to pack 29 cartons today .

To proof

As given

uhammad, a shipping and receiving clerk, uses 1 yard, 2 feet, 4 inches of twine to wrap each carton he packs.

As given in the question

Convert the answer to larger units .

As between  yard is the largest unit between yard, feet and inches.

1 inches = \frac{1}{36} yard

and

1 feet = \frac{1}{3} yard

Convert 2 feet into yard

=\frac{2}{3}

Convert 4 inches into yard

= \frac{4}{36}

twine to wrap each carton packs

= 1 + \frac{2}{3} + \frac{4}{36}

L.C.M of (3 , 36) = 36

than the equation becomes

=\frac{36 +2\times 12 + 4}{36}

= \frac{64}{36}

=1.77777778 yard

Now twine to wrap pack 29 cartons  = 29× 1.77777778

                                                             = 51.5555556 yard


Now twine to wrap pack 29 cartons is 51.55 yard ( approx)

Hence proved  

6 0
3 years ago
7/5=x/3 solve proportion
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Cross-multiply: 7 * 3 = 5 * x Divide each side by 5 : X = 7 * 3 / 5 = 4.2
6 0
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Please help with this math problem ASAP! I will give brainliest!
borishaifa [10]
  • x = 112°
  • y = 68°
  • z = 68°

Step-by-step explanation:

x = 112°

y = z = 180° - 112° = 68°

7 0
3 years ago
Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

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4 years ago
Part 1: Identify key features and graph a parabola from standard form.
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