Answer:
The probability of seeing both = 0.32
Step-by-step explanation:
<u>Step:-(i)</u>
Given data the probability that you see a butterfly during a nature center tour is 80%
Let 'B' be the event of butterfly during a nature center tour
The probability that you see a butterfly during a nature center tour is 80%
P(B) = 80% = 0.80
Given data the probability that you see a turtle is 40%
Let 'T' be the event of turtle a nature center tour
P(T) = 40% = 0.40
<u>Step:-(ii)</u>
<u>Independent events </u>
If the occurrence of the event B is not effected by the occurrence or non-occurrence of the event 'A' , then the event 'B' is said to be independent of 'A'
If A and B are independent events then
P(A ∩B) =P(A) P(B)
now the given data the butterfly and turtle are independent events
probability of seeing both
P(B∩T) = P(B).P(T)
= 0.80 × 0.40
= 0.32
Answer:
12.54
Step-by-step explanation:
Answer:
115
Step-by-step explanation:
Given :
Mean of intelligence score = 100
Standard deviation of intelligence score = 15
Since both are perfectly correlated,
The Zscore ON SAT = +1.0
Using the standard normal interpretation, Xcore on SAT of +1.0 means 1 standard deviation to the right
This means :
Mean + 1 standard deviation
100 + 1*15
= 115
We could use the Zscore formula directly too:
Zscore = (x - mean) / standard deviation
Zscore = +1 ; x = score
Hence, we have
1 = (x - 100) / 15
1 * 15 = x - 100
15 = x- 100
x = 15 + 100
x = 115
.875 seconds
a=360t
b=280t+(280*.25)
360t=280t+(280*.25)
360t=280t+70
80t=70
t=.875
