Ask question

Ask question

All categories

4 years ago

15

1, 1/5, 1/25,1/125 what’s the next number

2 answers:

Burka [1]4 years ago

5 0

Answer:

1/625

Step-by-step explanation:

As you can tell, the order is going by 1/5 times the number of how many times it was done

Svet_ta [14]4 years ago

3 0

Answer:

1/625

Step-by-step explanation:

1/5(5) =1/25(25)=1/125(125)=1/625

You might be interested in

Complete the point-slope equation of the line through (8,-8) and (9,8)<br> y-8=?

artcher [175]

Answer: y=0/1

Step-by-step explanation: I dint really get your question but if u were asking for slope there it is ! :)

5 0

4 years ago

Read 2 more answers

Just the answer please

UkoKoshka [18]

Answer:

201.06 cubic feet of confetti

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Find the diameter Who circumference is 62.8 feet use 3.14 for pie

Cloud [144]

Answer:

c) 20

Step-by-step explanation:

The circumference is given by

C= pi *d

Substitute in what we know

62.8 = 3.14*d

Divide by 3.14

62.8/3.14 =3.14d/3.14

20 =d

4 0

3 years ago

Please help me with my hw

stellarik [79]

Part 2 is 12.5 cm represents 5km
I worked this out by doing a ratio
5cm=2km
?cm=5km
you have to do 2 times 2.5 to get 5km so you do 5 times 2.5 to get 12.5cm
so the answer is that 12.5cm

6 0

3 years ago

Rectangle 1 has length x and width y. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of K, where k

STALIN [3.7K]

$\bold{\huge{\underline{\pink{ Solution }}}}$

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>Rectangle </u><u>1</u><u> </u><u> </u><u>has </u><u>length </u><u>x</u><u> </u><u>and </u><u>width </u><u>y</u>
<u>Rectangle</u><u> </u><u>2</u><u> </u><u>is </u><u>made </u><u>by </u><u>multiplying </u><u>each </u><u>dimensions </u><u>of </u><u>rectangle </u><u>1</u><u> </u><u>by </u><u>a </u><u>factor </u><u>of </u><u>k </u>
<u>Where</u><u>, </u><u>k </u><u>></u><u> </u><u>0</u><u> </u><u> </u>

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

Yes, The rectangle 1 and rectangle 2 are similar .

<h3><u>According </u><u>to </u><u>the </u><u>similarity </u><u>theorem </u><u>:</u><u>-</u></h3>

If the ratio of length and breath of both the triangles are same then the given triangles are similar.

<u>Let's </u><u>Understand </u><u>the </u><u>above </u><u>theorem </u><u>:</u><u>-</u>

The dimensions of rectangle 1 are x and y

<u>Now</u><u>, </u>

Rectangle 2 is made by multiplying each dimensions of rectangle 1 by a factor of k .

Let assume the value of K be 5

<u>Therefore</u><u>, </u>

The dimensions of rectangle 2 are

$\sf{ 5x \:and \:5y }$

<u>Now</u><u>, </u><u> </u><u>The </u><u>ratios </u><u>of </u><u>dimensions </u><u>of </u><u>both </u><u>the </u><u>rectangle </u><u>:</u><u>-</u>

$\bold{Rectangle 1 = Rectangle 2}$

$\bold{\dfrac{ x }{y}}{\bold{ = }}{\bold{\dfrac{5x}{5y}}}$

$\bold{\blue{\dfrac{ x }{y}}}{\bold{\blue{ = }}}{\bold{\blue{\dfrac{x}{y}}}}$

<u>From </u><u>above</u><u>, </u>

We can conclude that the ratios of both the rectangles are same

Hence , Both the rectangles are similar

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>Here</u><u>, </u>

We have to proof that, the

Perimeter of rectangle 2 = k(perimeter of rectangle 1 )

In the previous questions, we have assume the value of k = 5

<h3><u>Therefore</u><u>, </u></h3>

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

Perimeter of rectangle 1

$\sf{ = 2( length + Breath) }$

$\bold{\pink{= 2( x + y ) }}$

Thus, The perimeter of rectangle 1

Perimeter of rectangle 2

$\sf{ = 2( length + Breath) }$

$\sf{ = 2(5x + 5y) }$

$\sf{ = 2 × 5( x + y) }$

$\bold{\pink{= 10(x + y) }}$

Thus, The perimeter of rectangle 2

<u>According </u><u>to </u><u>the </u><u>given </u><u>condition </u><u>:</u><u>-</u>

Perimeter of rectangle 2 = k( perimeter of rectangle 1 )

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ 2(x + y) = 10(x + y)}$

$\bold{\pink{2x + 2y = 5(2x + 2y) }}$

<u>From </u><u>Above</u><u>, </u>

We can conclude that the, Perimeter of rectangle 2 is 5 times of perimeter of rectangle 1 and we assume the value of k = 5.

Hence, The perimeter of rectangle 2 is k times of rectangle 1

<h3><u>Answer 3 :</u></h3>

<u>Here</u><u>, </u>

We have to proof that ,

<u>The </u><u>area </u><u>of </u><u>rectangle </u><u>2</u><u> </u><u>is </u><u>k²</u><u> </u><u>times </u><u>of </u><u>the </u><u>area </u><u>of </u><u>rectangle </u><u>1</u><u>.</u>

<u>That </u><u>is</u><u>, </u>

Area of rectangle 1 = k²( Area of rectangle)

<h3><u>Therefore</u><u>, </u></h3>

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

<u>Area </u><u>of </u><u>rectangle </u><u>1</u>

$\sf{ = Length × Breath }$

$\sf{ = x × y }$

$\bold{\red{= xy }}$

<u>Area </u><u>of </u><u>rectangle </u><u>2</u>

$\sf{ = Length × Breath }$

$\sf{ = 5x × 5y }$

$\bold{\red{ = 25xy }}$

<u>According </u><u>to </u><u>the </u><u>given </u><u>condition </u><u>:</u><u>-</u>

Area of rectangle 1 = k²( Area of rectangle)

$\sf{ xy = 25xy }$

$\bold{\red{xy = (5)²xy }}$

<u>From </u><u>Above</u><u>, </u>

We can conclude that the, Area of rectangle 2 is (5)² times of area of rectangle 1 and we have assumed the value of k = 5

Hence, The Area of rectangle 2 is k times of rectangle 1 .

7 0

2 years ago