Answer:
[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2
Answer:
x = - 3 and x = 1
Step-by-step explanation:
Given the rational expression
The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Thus x = 1 and x = - 3 are both excluded values
Answer: 21, 22, 23
Step-by-step explanation:
you divide 66 with 3, that equals 22, then you have three 22. Then you have to take 1 from one of the 22s and give it to the other one, making it 21, 22 and 23
9lx−6x^2+6
It not 91 it the letter L just lower case