You get rid of any of the same bariables liike 3x-x is 2x so 2x+5 is the answer
and 
. So we have a remainder of
and 
. Subtracting this from the previous remainder gives a new remainder
and 
. Subtracting this from the previous remainder gives a new one of
and we're done since 2 does not divide 
. So we have
Answer:
The second option
Step-by-step explanation:
For this problem, there are multiple ways to solve. The easiest here is the cross method. For ax²+bx+c, you find 2 numbers that multiply to ac and add to b, which you replace b with.
ac in this case is -8×3, which is -24. b in this case is 23.
You can go through the factor pairs of -24 to find the ones that add to b. These pairs are (1 and -24, -1 and 24, 2 and -12, -2 and 12, 3 and -8, -3 and 8, 4 and -6, -4 and 6). The only pair that adds to 23 is 24 and -1.
You sub this into the original equation, making 3x²+24x-x-8.
From there, you factorise, making 3x(x+8)-x(x+8).
This can be factorised further to (3x-x)(x+8) by collecting like terms.
**This question involves factorising quadratics, which you may wish to revise. I'm always happy to help!
Answer:
Refer the photos above and have a good day
Answer:
Give the digits in the hundreds place and the tens place.
7,853
Step-by-step explanation:
