So the equation is (base *height)/2
In this case: 12*17= 204
204/2=102 in^3
I hope I lead you to the right path. Im sorry if I am wrong.
75/15 is one of them. Not sure about the rest
Remember, you can do anything to an equation as long as you do it to both sides
we hates fractions
times both sides by 3
(we could have added 1/3b to both sides but I'm lazy)
4b+6=12-b
add b to both sides
5b+6=12
minus 6 both sides
5b=6
divide both sides by 5
Answer:
the answer is c.(3,-3)
:)
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
The formula for area of a trapezoid is: 1/2 (b1+b2) h
b1=10
b2=10·2=20 because it stated the side parallel is twice as long as the side above
h=10/2=5 because the height is half as long as the give side length
area of the trapezoid is: 1/2 (10+20) 5
(5·10)·5
50·5
area of the trapezoid is 250 in²