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Mariulka [41]
3 years ago
9

How does salt help melt the road?​

Chemistry
2 answers:
QveST [7]3 years ago
8 0

Lower the melting point

Explanation:

Salts helps to melt road by lowering the melting point. It acts as an impurity and generally, impurities low the melting point of substances.

Salts are used as an antifreeze.

  • Water freezes at 0°C and forms ice/snow which can impede human and vehicular movement.
  • When salt is added, it causes the depression of the freezing point by lowering it further.
  • The freezing point is pegged back at -6°C.
  • This way it takes more low temperature to freeze the water.
  • The salt acts as an impurity and causes the depression of melting point and widening of the melting range.

learn more:

Matter brainly.com/question/10972073

#learnwithBrainly

MA_775_DIABLO [31]3 years ago
7 0

Answer:

Salt is added to icy roads in the winter because it lowers the freezing point of water, which also makes the salt melt the ice.

Explanation:

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How many grams of sodium chloride are present in a 0.75 M solution with a volume of 500.0 milliliters?
saveliy_v [14]
The molarity of a solution is a type of expression of concentration equal to the number of moles solute per liter solution. In this problem, we are given the molarity equal to 0.75 M and a volume equal to 500 milliliters. <span>500 milliliters is equal to 0.5 liters. we multiply M and L to get the number of moles then multiply by the molar mass of NaCl. The answer is 21.92 grams.</span>
6 0
3 years ago
Predict the splitting pattern for each of the labeled hydrogens in the following molecules. Assume that all coupling constants a
Ghella [55]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

b) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

c) The IUPAC name is Butan-2-ol

Explanation:

Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.

According to that for molecule 1 as shown on the second uploaded image

For Proton Ha, number of non equivalent protons n= 2

Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

Considering the second question for Molecule 2 as shown on the third uploaded image  

For Proton Ha, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

For Proton Hb, number of non equivalent protons n= 3

Splitting pattern for Hb= 3+1=4 , Quartet

For Proton Hc, number of non equivalent protons n= 3

Splitting pattern for Hc= 3+1=4 , Quartet

For Proton Hd, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

Considering the third question

The name of the given molecule  is gotten according to longest carbon chain  = 4 (Prefix 'Butan')

Functional group = -OH (Suffix 'ol') at C-2

The IUPAC name is Butan-2-ol

3 0
3 years ago
The volume of gas occupied 240.0ml when the pressure is 1.20 atm what volume at constant pressure.will the gas occupies when the
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Answer:

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Explanation:

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7 0
2 years ago
How can an experiment support or fail a hypothesis
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A hypothesis is given to explain a phenomena which has not been explained till then. it can be supported by an experiment if that experiment gets the other results regarding that particular phenomena in agreement with that being predicted by the hypothesis
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A sample of gas occupies a volume of 445 mL at a temperature of 274 K. At what temperature will this sample of gas occupy a volu
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V1 = 445ml V2 = 499ml
T1 = 274 K T2 = ?

By Charles Law,
V1/T1 = V2/T2
445/274 = 499/T2
By solving we get,
T2 = 307.25 K
4 0
3 years ago
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