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Doss [256]
3 years ago
9

How many moles of water can be made when 48 moles of HNO3 are consumed?

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
6 0
That’s hard and I don’t know
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Given the following isotopes of strontium, calculate the average atomic mass.
vodka [1.7K]

Answer:

87.5198

Explanation:

(43.65 * 87.05) + (48.25 * 87.93) + (8.11 * 87.50) = 8751.98

8751.98 / 100 = 87.5198

3 0
3 years ago
Complete the following reaction :<br><br>HC≡CH + HBr→? ​
Morgarella [4.7K]

hope it helps you .............

3 0
2 years ago
IF 14.07*10^26 molecules of magnesium chloride was produced in the following reaction, how many grams of magnesium reacted?
Wittaler [7]

Answer:

56160grams

Explanation:

First, we need to convert the number of molecules of magnesium chloride (MgCl2) into moles by dividing by Avagadro's number (6.02 × 10^23 molecules)

n = nA ÷ 6.02 × 10^23

n = 14.07 × 10^26 ÷ 6.02 × 10^23

n = 14.07/6.02 × 10^(26-23)

n = 2.34 × 10^3 moles of MgCl2

The balanced reaction given in the question is as follows:

Mg + 2HCl → MgCl2 + H2

If 1 mole of Mg produced 1 mole of MgCl2

Then, 2.34 × 10^3 moles of Mg will also produce 2.34 × 10^3 moles of MgCl2.

Using mole = mass ÷ molar mass (MM)

Molar mass of Mg = 24g/mol

mass = mole × MM

mass = 2.34 × 10^3 × 24

mass = 56.16 × 10^3

mass = 56160grams.

6 0
3 years ago
Enter a chemical equation for HI(aq) showing how it is an acid or a base according to the Arrhenius definition. Consider that st
jek_recluse [69]

Answer:

HI (aq) → H⁺ (aq) +  I⁻ (aq)

HI (aq) +  H₂O(l)  → H₃O⁺ (aq) +  I⁻ (aq)

Explanation:

The Arrhenius acid concept indicates that a substance behaves like acid if it produces hydrogen ions H⁺ or hydronium ions H₃O⁺ in water. A substance will be classified as a base if it produces OH⁻  hydroxide ions in water. This way of defining acids and bases works well for aqueous solutions.

When we mix HI (aq) and water, we are increasing [H₃O⁺]

HI (aq) → H⁺ (aq) +  I⁻ (aq)

HI (aq) +  H₂O(l)  → H₃O⁺ (aq) +  I⁻ (aq)

7 0
3 years ago
What is the molarity of a solution that contains 20.45 g of sodium chloride (NaCl) dissolved in 700.0 mL of solution?
Nostrana [21]
Molarity is the number of moles of solute in 1 L of solution.
the mass of NaCl added - 20.45 g
number of moles of NaCl - 20.45 g / 58.5 g/mol = 0.350 mol
volume of the solution is 700.0 mL 
since molarity is the number of moles in 1000 mL 
and if 700.0 mL contains - 0.350 mol 
therefore 1000 mL contains - 0.350 mol / 700.0 x 1000 = 0.500 mol 
hence molarity of solution is 0.500 M
6 0
3 years ago
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