How many moles of water can be made when 48 moles of HNO3 are consumed?

It is relatively easy to change the temperature of a substance that:_______

Taya2010 [7]

Answer:

b. has a low specific heat capacity.

Explanation:

Hello,

In this case, since the specific heat is defined as the heat required to increase or decrease 1 degree Celsius 1 gram or mole of a specific substance, we infer that the lower the specific heat, the less energy will be needed for such increase or decrease, therefore, it turns out easier to modify the temperature in a substance that b. has a low specific heat capacity.

Best regards.

4 0

3 years ago

The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick

Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

Length x breadth x thickness

18cm x 8cm x 5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part = length x breadth = 18cm x 8cm = 144cm

The area of the widest part of the figure is 144cm²

4 0

3 years ago

Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu

nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,

$Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)$

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

$E^0_{[Pb^{2+}/Pb]}=-0.13V$

$E^0_{[Cu^{2+}/Cu]}=+0.34V$

$E^0_{cell}=E^0_{cathode}-E^0_{anode}$

$E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}$

$E^0_{cell}=-0.13V-(0.34V)=-0.47V$

Now we have to calculate the standard Gibbs free energy.

Formula used :

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant = 96500 C/mole

$E^o$ = standard e.m.f of cell = -0.47 V

Now put all the given values in this formula, we get the Gibbs free energy.

$\Delta G^o=-(2\times 96500\times (-0.47))=+90710J/mole=+90.71kJ/mole\approx +91kJ/mole$

Therefore, the standard Gibbs free energy is +91 kJ/mole

6 0

2 years ago

What happens to the electron cloud at very high atomic numbers, when the innermost electrons would, using a non-relativistic mod

marin [14]

Answer:

tough question

Explanation:

8 0

1 year ago

using the equation you wrote determine how many moles of butane c4h10 are needed to react with 5.5 moles of oxygen

GaryK [48]

Answer:

0.846 moles.

Explanation:

This is a stichiometric problem.

The balanced equation of complete combustion of butane is:

C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

It is clear from the stichiometry of the balanced equation that complete combustion of 1.0 mole of butane needs 6.5 moles of O₂ to produce 4 moles of CO₂ and 5 moles of H₂O.

<u><em>Using cross multiplication:</em></u>

1.0 mole of C₄H₁₀ reacts with → 6.5 moles of O₂

??? moles of C₄H₁₀ are needed to react with → 5.5 moles of O₂

The number of moles of C₄H₁₀ that are needed to react with 5.5 moles of O₂ = (1.0 x 5.5 moles of O₂) / (6.5 moles of O₂) = 0.846 moles.

3 0

3 years ago