Answer:
Total protein range. The normal range for total protein is between 6 and 8.3 grams per deciliter (g/dL). This range may vary slightly among laboratories.
Explanation:
Answer:
Light
Explanation:
Plant is a thing so it has matter
Cheese is food so it has matter
Blood is a liquid so it has matter
Answer:
Igneous=B
Sedimentary=C
Metamorphic=A
Weathering is when=B
If sedimentary rock.....=C
The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.
Further Explanation:
To solve this problem, follow the steps below:
- Write the balanced chemical equation for the given reaction.
- Convert the mass of calcium carbonate into moles.
- Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
- Convert the number of moles of calcium oxide into mass.
Solving the given problem using the steps above:
STEP 1: The balanced chemical equation for the given reaction is:
![CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}](https://tex.z-dn.net/?f=CaCO_%7B3%7D%20%5Crightarrow%20%5C%20CaO%20%5C%20%2B%20%5C%20CO_%7B2%7D)
STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.
![mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}](https://tex.z-dn.net/?f=mol%20%5C%20CaCO_%7B3%7D%20%5C%20%3D%2025%20%5C%20g%20%5C%20CaCO_%7B3%7D%20%5C%20%28%5Cfrac%7B1%20%5C%20mol%20%5C%20CaCO_%7B3%7D%7D%7B100.0869%20%5C%20g%20%5C%20CaCO_%7B3%7D%7D%29%5C%5C%20%5C%5C%5Cboxed%20%7Bmol%20%5C%20CaCO_%7B3%7D%20%5C%20%3D%200.2498%20%5C%20mol%7D)
STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.
For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,
![mol \ CaO \ = 0.2498 \ mol](https://tex.z-dn.net/?f=mol%20%5C%20CaO%20%5C%20%3D%200.2498%20%5C%20mol)
STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.
![mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g](https://tex.z-dn.net/?f=mass%20%5C%20CaO%20%5C%20%3D%200.2498%20%5C%20mol%20%5C%20CaO%20%5C%20%28%5Cfrac%7B56.0774%20%5C%20g%20%5C%20CaO%7D%7B1%20%5C%20mol%20%5C%20CaO%7D%29%5C%5C%20%5C%5Cmass%20%5C%20CaO%20%5C%20%3D%2014.008%20%5C%20g)
Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.
Therefore,
![\boxed {mass \ CaO \ = 14 \ g}](https://tex.z-dn.net/?f=%5Cboxed%20%7Bmass%20%5C%20CaO%20%5C%20%3D%2014%20%5C%20g%7D)
Learn More
- Learn more about stoichiometry brainly.com/question/12979299
- Learn more about mole conversion brainly.com/question/12972204
- Learn more about limiting reactants brainly.com/question/12979491
Keywords: thermal decomposition, stoichiometry