1. Water is easily contaminated by both biological and chemical contaminants. Define and give 3 examples of each

The chemical properties of an atom are primarily determined by the number of

natulia [17]

Chemical properties are mainly determined by the number of valence electrons (electrons which can be gained, lost, or shared) in the atom.

5 0

3 years ago

At 218°C, Keq=1.2 x 10^-4 for the equilibrium NH4SH(s) ⇋ NH3(g) + H2S(g). Calculate the equilibrium concentrations of NH3 and H2

maksim [4K]

At 218 °C, solid NH₄SH decomposes to form 0.011 M NH₃ and H₂S, as given by its equilibrium constant.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant (Keq) is the ratio of the product of the concentrations of the products to the product of the concentrations of the reactants, all raised to their stoichiometric coefficients.

Only gases and aqueous species are included.

Step 1. Make an ICE chart.

NH₄SH(s) ⇋ NH₃(g) + H₂S(g)

I 0 0

C +x +x

E x x

Step 2. Write the equilibrium constant.

Keq = 1.2 × 10⁻⁴ = [NH₃] [H₂S] = x²

x = 0.011 M

At 218 °C, solid NH₄SH decomposes to form 0.011 M NH₃ and H₂S, as given by its equilibrium constant.

Learn more about equilibrium here: brainly.com/question/5081082

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3 0

2 years ago

What are epimers? How are glucose and manose epimers? Please Help!

katrin2010 [14]

Answer:

PLZ MARK ME BRIANLIEST I REALLY WANT IT PLZZZZZZ ISS GARIB KI DUA LAGEGI YARR PLZ

Explanation:

Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.

4 0

2 years ago

Read 2 more answers

A tire is filled to a gauge pressure of 2 atm at 27 degrees Celsius after a drive the temperature within the tire rises to 47 de

Ivenika [448]

Answer:

2.13atm

Explanation:

The following information were obtained from the question:

P1 (initial pressure) = 2atm

T1 (initial temperature) = 27°C = 27 + 273 = 300K

T2 (final temperature) = 47°C = 47 + 273 = 320K

P2 (final pressure) =?

Using the equation P1/T1 = P2/T2, the final pressure within the tyre can be obtained as illustrated below:

P1/T1 = P2/T2

2/300 = P2/320

Cross multiply to express in linear form

300 x P2 = 2 x 320

Divide both side by 300

P2 = (2 x 320)/300

P2 = 2.13atm

Therefore, the pressure within the tyre at 47°C is 2.13atm

4 0

3 years ago

I WILL MARK YOUR BRAINLIEST HELP! 0.023 kg= blank cg Means a lot

Karolina [17]

Can you add more context to your question i’m confused

4 0

3 years ago