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4 years ago

What is the function of nucleus in plant and animal cells

1 answer:

tatiyna4 years ago

8 0

In animal cells, vacuoles are generally small. Vacuoles tend to be large in plant cells and play several roles: storing nutrients and waste products, helping increase cell size during growth, and even acting much like lysosomes of animal cells. The plant cell vacuole also regulates turgor pressure in the cell.

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The radioactive element radium (Ra) decays by a process known asalpha decay,in which the nucleus emits a helium nucleus. (Factoi

tamaranim1 [39]

<u>Answer:</u> The energy released in the decay process is $4.6800\times 10^{11}J$

<u>Explanation:</u>

The equation for the alpha decay of Ra-226 follows:

$_{88}^{226}\textrm{Ra}\rightarrow _{2}^{4}\textrm{He}+_{86}^{222}\textrm{Rn}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Rn}+m_{He})-(m_{Ra})$

We know that:

$m_{Rn}=222.0176u\\m_{Ra}=226.0254u\\m_{He}=4.0026u$

Putting values in above equation, we get:

$\Delta m=(222.0176+4.0026)-(226.0254)=-0.0052g=-5.2\times 10^{-6}kg$

(Conversion factor: 1 kg = 1000 g )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(-5.2\times 10^{-6}kg)\times (3\times 10^8m/s)^2$

$E=-4.6800\times 10^{11}J$

Hence, the energy released in the decay process is $4.6800\times 10^{11}J$

8 0

3 years ago

Which property of a substance can determine using a ph indicator

vagabundo [1.1K]

Answer:

The acidic or the basic nature of a substance can be determined using a pH indicator. If the pH indicator , shows a pH value less than 7 , the substance is acidic. Lower the pH , high is the acidic nature.

Explanation:

7 0

3 years ago

5. Confirm dimensionally that the product (lvp/n) is

Sidana [21]

Answer:

How do you do it?

Explanation:

7 0

3 years ago

A 10.0kg of desk initial is pushed along a frictionless surface by a constant horizontal of force magnitude 12N Find the speed o

Simora [160]

kylydljty many true dvx*&;'*+$_5+

3 0

3 years ago

If one doubles the emfs in a circuit and doubles the resistances in the circuit at the same time, what happens to the currents t

bija089 [108]

Answer:

Same

Explanation:

Let R be the resistance of the cell and E be the emf.

Let i be the current in the circuit.

i = E / R ..... (1)

Now emf and resistance be doubled.

so, i' = 2E/2R = E/R

So, i' = i (From equation (1)

Current remains same.

3 0

3 years ago