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Nutka1998 [239]
4 years ago
5

O

Physics
1 answer:
natima [27]4 years ago
4 0
Ghanaian habahhaha ajajajaba
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A battery is two or more individual cells connected together. Some large trucks utilize large 24 volt lead acid batteries. How m
uranmaximum [27]

Answer:

 #_pile = 12 celdas

Explanation:

Lead acid sulfur batteries generate each cell a potential of 2 volts. By colonato to reach the voltage of 24 volts

        #_pile = 24/2

       #_pile = 12 cledas

serially connected

5 0
3 years ago
State Ohms law in easy words
Alexus [3.1K]

Answer:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

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What kind of object are the light rays interacting with in the model below?
Ymorist [56]

Answer:

Concave lens

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5 0
2 years ago
I need to know what the answer is to this
Arturiano [62]
A pull between two objects, for example, between an object and Earth. When forces on an object are balanced, there is no change in speed or direction.

So the answer is I agree
7 0
2 years ago
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A sound from a source has an intensity of 270 dB when it is 1 m from the source.
Rufina [12.5K]
Remember that sound intensity decreases in inverse proportion to the distance squared. So, to solve this we are going to use the inverse square formula: \frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
where
I_{2} is the intensity at distance 2
I_{1} is the intensity at distance 1
d_{2} is distance 2
d_{1} is distance 1

We can infer for our problem that I_{1}=270, d_{1}=1, and d_{2}=3. Lets replace those values in our formula to find I_{2}:
\frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
\frac{I_{2} }{270} =( \frac{1}{3} )^2
\frac{I_{2} }{270} = \frac{1}{9}
I_{2}= \frac{270}{9}
I_{2}=30 dB

We can conclude that the intensity of the sound when is <span>3 m from the source is 30 dB.</span>
8 0
3 years ago
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