Given Information:
Mass = m = 95 kg
Initial velocity = v₁ = 0 m/s
Final velocity = v₂ = 3 m/s
time = t = 15 seconds
Required Information:
magnitude of average force = ?
Answer:
magnitude of average force = 19 N
Explanation:
From the Newton's second law of motion
F = ma
From the kinematics equations,
v₂ = v₁ + at
at = v₂ - v₁
a = (v₂ - v₁)/t
a = (3 - 0)/15
a = 0.2 m/s²
F = 95*0.2
F = 19 N
Therefore, the magnitude of the average force required to bring the sled to rest is 19 N.
Answer:
The velocity of the skateboard is 0.774 m/s.
Explanation:
Given that,
The spring constant of the spring, k = 3086 N/m
The spring is stretched 18 cm or 0.18 m
Mass of the student, m = 100 kg
Potential energy of the spring,
To find,
The velocity of the car.
Solution,
It is a case of conservation of energy. The total energy of the system remains conserved. So,
v = 0.774 m/s
So, the velocity of the skateboard is 0.774 m/s.
The box of 15 baseballs because it has more weight.
Answer:
d=10.3g/cm³
Explanation:
density is defined as the ratio of mass of an object to its mass volume.
d= m/V
Substitute the values given in the problem
d=(103g)/(10cm³)
d=10.3g/cm³
Answer:
402 nm .
Explanation:
Let the wave length of unknown light be λ .
For fifth order maxima the condition is
path difference at the point of fringe = 5 λ
For red light of 670 nm , for 3 rd order maxima
path difference at the point of fringe = 3 x wave length
= 3 x 670 nm
From these two equations
5 λ = 3 x 670 nm
λ = 3 x 670 / 5 nm
= 402 nm .