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3 years ago

What is the surface area of a box that is 20.1 m long, 6.8 m wide and 7.4 m high?

Mathematics

1 answer:

blsea [12.9K]3 years ago

6 0

Answer:

Surface area of the box is $=671.48m^2$

Step-by-step explanation:

The box is in the shape of a cuboid:

Surface area of the cuboid = 2(L*W+W*H+H*L)

Length(L)=20.1 m

Width(W)=6.8 m

Height(H)=7.4 m

Surface area:

$2((20.1*6.8)+(6.8*7.4)+(7.4*20.1))\\\\=2(136.68+50.32+148.74)\\\\=2(335.74)\\\\\=671.48m^2\\\\$

The surface area of the box is $=671.48m^2$

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