<img src="https://tex.z-dn.net/?f=1%20%5Cdiv%201%20%2B%20a%20%20%7Bl%7D%20-%20%7Bm%7D%20%20%2B%201%20%5Cdiv%201%20%2B%20%20%7Bm%

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3 years ago

7D%20-%20%7Bl%7D%20" id="TexFormula1" title="1 \div 1 + a {l} - {m} + 1 \div 1 + {m} - {l} " alt="1 \div 1 + a {l} - {m} + 1 \div 1 + {m} - {l} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

ziro4ka [17]3 years ago

6 0

Answer:

Using BODMAS

first solve division, then go for addition or subtraction

$1 \div 1 + al - m + 1 \div 1 + m - l\\ =(1 \div 1) + al - m +( 1 \div 1) + m - l\\ =1 + al - m + 1 + m - l\\ = 2 + al -l\\=2 + l(a - 1)$

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Answer:

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2 years ago

Use greatest common factor and the distributive property to write equivalent expressions in factored form for the following expr

Nitella [24]

Answer:

a. 4(d+3e)

b. 6(3x+5y)

c. 7(3a+4y)

d. 8(3f+7g)

Step-by-step explanation:

In each case we find the greatest common factor of the numbers. That is the greatest number that goes into both the numbers. Then we factor it out in front and inside parentheses we divide each original term by the greatest common factor:

a. 4d+12e, GCF: 4

$\displaystyle4\left(\frac{4d}{4}+\frac{12e}{4}\right)=4(d+3e)$

b. 18x+30y, GCF: 6

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c. 21a+28y, GCF: 7

$\displaystyle7\left(\frac{21a}{7}+\frac{28y}{7}\right)=7(3a+4y)$

d. 24f+56g, GCF: 8

$\displaystyle8\left(\frac{24f}{8}+\frac{56g}{8}\right)=8(3f+7g)$

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3 years ago

What is the answer?

kenny6666 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Can someone please help me with these questions (picture)

Alexxx [7]

Step-by-step explanation:

Answer 1 to find the base to apply the Pythagoras theorem..of finding length..

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3 years ago

Read 2 more answers

1. 3x + x - 2x + 8 = 3x + x

FinnZ [79.3K]

Step-by-step explanation:

1. 3x+x-2x+8=3x+x

x-2x+8=x

x+8=x+2x

8=2x

8÷2=4

x=4

2. 2(2x+4)-2x=x+18

8+4x-2x=x+18

8+2x=x+18

2x=x+10

x=10

3. 2(x+3)+3x

2(5+3)+15

16+15

4. 3(2x)-3x+4=2x+5

6x-3x+4=2x+5

3x+4=2x+5

3x-2x+4=5

x=1

5. 3x+2x+x=x+6

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5x=6

x=6/5

6. 2(x+4)+x=16

2x+8+x=16

3x+8=16

3x=8

x=8/3

Hope I calculated it right you can check it in calculator

3 0

3 years ago