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spayn [35]
3 years ago
11

The answer's are in the image sorry if you cant see them

Mathematics
1 answer:
Simora [160]3 years ago
8 0
C. "David's equation is correct, because their spending will be multiplied by the number of months and then subtracted from their savings"

they are technically saying "Look we have 12,350 to use. How long (y) will the savings (12,350) last after using 240 each month (x)
so the amount they use *PER* month gets subtracted from the savings because they are using that money to pay with

Hope this helps :)
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Two numbers are consecutive integers. Six times the smaller integer equals three times the greater integer. Find the integers​
Oduvanchick [21]
Sorry can’t help I wish I court could opt mrlrnrk is the year or
3 0
3 years ago
Help pls. i’m taking a geometry quiz and don’t really understand
kramer
Mw is 118 because a whole circle equals 360. you would do 360= 156+86+mw
5 0
3 years ago
Solve the math problem
zalisa [80]

Answer:

\frac{4w {}^{8} }{9m {}^{4} }

Step-by-step explanation:

separate with like terms

\frac{4}{9} , \:  \frac{w {}^{9} }{w}  \: and \: \:  \frac{m {}^{5} }{m {}^{9} }

the first fraction can be left alone as it can't be simplified any further

the second fraction can be written as w⁹ ÷ w¹ , when the bases are the same and division is involved subtract the powers: 9 - 1 = 8, so it's simplified to w⁸

the third fraction can be written as m⁵ ÷ m⁹, subtract the powers: 5 - 9 = -4, so it's simplified to m⁻⁴

{m}^{ - 4}  =  \frac{1}{m {}^{4} }

putting it together:

\frac{4w {}^{8} }{9m {}^{4} }

4 0
2 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
4 years ago
F(3) =-2x^2+9x+5 calculate the following
ElenaW [278]

Answer:

50

Step-by-step explanation:

2(3)^2+9(3)+5

2(9)+27+5

18+27+5

=50

8 0
3 years ago
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