Ask question

Ask question

All categories

2 years ago

10

Khairul deposited $ 600 in a bank at the end of 2010 and another $ 400 in the same bank at the end of 2011. The bank offers simp

le interest at a rate of 3% per annum. Find the total amount he has in his bank at the end of 2013.
the answer is 1078 .
(But how )

1 answer:

castortr0y [4]2 years ago

5 0

Answer:

bat puro math pede history lng

You might be interested in

A correlation coefficient of _____ indicates that the variables form a perfect linear relationship.

serg [7]

A correlation coefficient of 1 or -1 indicates that the variables form a perfect linear relationship.

8 0

2 years ago

The dimensions for a rectangular prism are x + 2 for the length, x + 3 for the width, and x for the height. What is the volume o

Jlenok [28]

V = lwh

V = (x + 2)(x + 3)(x)

V = (x)(x^2 + 3x + 2x + 6)

V = (x^3 + 3x^2 + 2x^2 + 6x)

V = x^3 + 5x^2 + 6x

All you do is foil the dimensions together and then combine like terms. Hope this helps!

7 0

2 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

5.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

8.

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

1 year ago

Im timed make it quick

erica [24]

Answer:

i think its a

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve: In 2x + In 2 = 0<br> DONE

pychu [463]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

We can use some logarithmic rules to solve this easily.

<em>Note: Ln means $Log_e$ </em>

<em />

Now, lets start with the equation:

$ln(2x) + ln(2) = 0\\ln(2x) = -ln(2)$

Writing left side with logarithmic base e, we have:

$Log_{e}(2x) = -ln(2)$

We can now use the property shown below to make this into exponential form:

$Log_{a}b=x\\means\\a^x=b$

So, we write:

$Log_{e}(2x) = -ln(2)\\e^{-ln(2)}=2x$

We recognize another property of exponentials:

$a^{bc}=(a^{b})^{c}$

So, we write:

$e^{-ln(2)}=2x\\(e^{ln(2)})^{-1}=2x$

Also, another property of natural logarithms is:

$e^{(ln(a))}=a$

Now, we simplify:

$(e^{ln(2)})^{-1}=2x\\(2)^{-1}=2x\\\frac{1}{2}=2x\\x=\frac{\frac{1}{2}}{2}\\x=\frac{1}{4}$

This is the answer.

7 0

3 years ago