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3 years ago

What is the solution set of x^2+y^2=26 and x-y=6?

Mathematics

1 answer:

lubasha [3.4K]3 years ago

5 0

I think it's B because it's makes the most sense

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What is the area<br> of circle <br><br><br><br>with a diameterms of 10 m

pentagon [3]

Answer:

exact area = 25(pi) m^2

approximate area = 78.54 m^2

Step-by-step explanation:

diameter = 10 m

radius = diameter/2 = 10 m / 2 = 5 m

area = (pi)r^2

area = (pi)(5 m)^2

area = 25(pi) m^2

area = 78.54 m^2

6 0

3 years ago

Select all the statements that are true about standard deviation.

frozen [14]

Answer:

A,B, C

Step-by-step explanation:

hope it helps

7 0

3 years ago

Charlie invests £1200 at 3.5% per annum compound interest.

lbvjy [14]

Answer:

Step-by-step explanation:

Using the compound interest formula $A = P(1+\frac{r}{n} )^{nt}$

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P = £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

$A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46$

Value of Charlie's investment after 3 years is £1,330.46

6 0

3 years ago

If a simple machine reduces the strength of a force, what must be increased?

ch4aika [34]

I think the answer is C. The distance over which the force is applied. Hope this helps!

4 0

3 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.

3 0

4 years ago