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QveST [7]
3 years ago
11

What is the solution set of x^2+y^2=26 and x-y=6?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0
I think it's B because it's makes the most sense
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A flagpole casts a shadow that is 85 feet long. Paul is 6 feet tall, and while standing next to the flagpole, casts a shadow tha
hammer [34]

Answer:

51m

Step-by-step explanation:

-Paul is 6ft, and has a 10ft shadow. The pole has a 85ft shadow:

-Using ratios:

\frac{Height\ of \ object}{Height\ of \  shadow}

Let h be the height of the flagpole:

=>\frac{6}{10}=\frac{h}{85}\\\\h=\frac{6\times 85}{10}\\\\h=51

Hence, the height of the pole is 51m

6 0
3 years ago
How do you do these questions?
Lady bird [3.3K]

Answer:

(e) csc x − cot x − ln(1 + cos x) + C

(c) 0

Step-by-step explanation:

(e) ∫ (1 + sin x) / (1 + cos x) dx

Split the integral.

∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx

Multiply top and bottom of first integral by the conjugate, 1 − cos x.

∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx

Pythagorean identity.

∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx

Divide.

∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx

Integrate.

csc x − cot x − ln(1 + cos x) + C

(c) ∫₋₇⁷ erf(x) dx

= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx

The error function is odd (erf(-x) = -erf(x)), so:

= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx

= 0

7 0
3 years ago
In a list of 100 numbers , the fraction of numbers greater than 15 is (19/25) and the fraction of numbers less than 15 is (7/50)
Bingel [31]
19/25 * 100 = 1900/25 = 76 ....numbers greater then 15
7/50 * 100 = 700/50 = 14....numbers less then 15

100 - (76 + 14) = 100 - 90 = 10 <== numbers equal to 15
6 0
3 years ago
A cylinder-shaped drainage pipe 66 in. long measures 25.12 in. around.
Darina [25.2K]
V=hpir^2

tricky, they didn't give us radius
they just gave circiufmerece

c=2pir
25.12=2pir
divide by 2 both sides
12.56=pir
divide by 3.14 both sides
4=r

subsitutet

v=hpir^2
v=66pi4^2
v=66pi16
v=1056pi
v=3315.84 cubic inches

4 0
3 years ago
the midpoint is AB is M(3,-2). One endpoint is A(7,-9). Find the coordinates of the other endpoint B.
cestrela7 [59]

Answer:

<em>The required points of the given line segment  are ( - 1, - 5 ).</em>

Step-by-step explanation:

Given that the line segment AB whose midpoint M is ( 3, -2 ) and point A is ( 7, - 9), then we have to find point B of the line segment AB -

As we know that-

If a line segment AB is with endpoints ( x_{1}, y_{1} ) and  ( x_{2}, y_{2}  )then the mid points M are-  

<em>M = ( \frac{ x_{1} + x_{2} }{2} , \frac{ y_{1} + y_{2}  }{2}  )</em>

Here,

<em>Let A ( 7, - 9 ), B ( x, y ) with midpoint M ( 3, - 2 ) -</em>

then by the midpoint formula M are-

<em>( 3, - 2 )  = ( \frac{ 7 + x}{2} , \frac{ - 9 + y}{2} )</em>

On comparing x coordinate and y coordinate -

We get,

<em>( \frac{ 7 + x}{2} = 3  , \frac{ - 9 + y}{2}  = - 2)</em>

<em>( 7 + x = 6, - 9 + y = - 4 )</em>

<em>( x = 6 - 7, y = - 4 + 9 )</em>

<em>( x = - 1, y = -5 )</em>

<em>Hence the required points  A are ( - 1, - 5 ).</em>

<em>We can also verify by putting these points into Midpoint formula.</em>

<em />

8 0
3 years ago
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