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Reil [10]
3 years ago
6

How do you Write 29/9 as a mixed number.

Mathematics
2 answers:
melomori [17]3 years ago
6 0
29 = 3 x 9 + 2

\frac{29}{9}=3\frac{2}{9} 
Oksi-84 [34.3K]3 years ago
4 0
To write an improper fraction a mixed number you start by seeing how many times the denominator (bottom number) goes in to the numerator (top number). Since the denominator is 9 and the numerator is 29, 9 goes into 29 3 times. The left over numbers become the fraction of which is in simplest form.
<em>3 x 9 = 27</em>
<em>29 - 27 = 2</em>

<u>Mixed number: 3 2/9</u>
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Nady [450]

Answer:

<u>$131.66</u>

Step-by-step explanation:

50 percent off 249.00 is 124.50

Then 124.50 including a sales tax of 5.75$

Would Be <u>$131.66</u>

------------------------------------------------------------------

<em><u>Hope this Helps!!! :)</u></em>

If you have any more questions feel free to ask!

5 0
2 years ago
HELP FAST PLS ILL LOVE U FOREVER &lt;3 Angle ABC is 47 degrees. What is the the measure of angle CBD?
AysviL [449]

Answer:

43

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Pc Richard and son are selling a drone for 179.99 for 10% off and $20 off to the first 100 customers what’s the price
den301095 [7]

Answer:

The price for the first 100 customers is $142.00.

Step-by-step explanation:

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3 0
3 years ago
Over what interval will the immediate value theorem apply
koban [17]

Answer:

Any [a,b] that does NOT include the x-value 3 in it.

Either an [a,b] entirely to the left of 3, or

an  [a,b] entirely to the right of 3

Step-by-step explanation:

The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.

Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.

6 0
3 years ago
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valina [46]
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The peddler made $54 profit.
5 0
3 years ago
Read 2 more answers
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