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2 years ago

Subtract (-8+2x^3) from (3x^3-4-3x)

Mathematics

2 answers:

konstantin123 [22]2 years ago

5 0

3x^3-4-3x-(-8+2x^3)
-> 3x^3-4-3x+8-2x^3
-> x^3-3x+4

Harman [31]2 years ago

3 0

$\to \sf(3x^3-4-3x) - (-8+2x^3)$

$\to \sf(3x^3-4-3x) + 8 - 2x^3$

$\to \sf3x^3-4-3x + 8 - 2x^3$

$\to \sf3x^3 - 2x^3-3x +4$

$\to \sf x^3-3x +4$

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Step-by-step explanation:

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The area of the bottom rectangular face is $10(12)=120$ .

So, the total surface area is $120+156+134=\boxed{410 \text{ km}^{2}}$

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