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nexus9112 [7]
3 years ago
15

Subtract (-8+2x^3) from (3x^3-4-3x)

Mathematics
2 answers:
konstantin123 [22]3 years ago
5 0
3x^3-4-3x-(-8+2x^3)
-> 3x^3-4-3x+8-2x^3
-> x^3-3x+4
Harman [31]3 years ago
3 0

\to \sf(3x^3-4-3x) - (-8+2x^3)

\to \sf(3x^3-4-3x)  + 8 - 2x^3

\to \sf3x^3-4-3x  + 8 - 2x^3

\to \sf3x^3 - 2x^3-3x  +4

\to \sf x^3-3x  +4

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(10.02)
ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

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6 0
3 years ago
-12+x-34=60<br> If you like this question please rate this five stars!<br> Thank you!
natulia [17]

Answer:

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Step-by-step explanation:

Let's solve your equation step-by-step.

−12+x−34=60

Step 1: Simplify both sides of the equation.

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−12+x+−34=60

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8 0
3 years ago
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