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2 years ago

15

Subtract (-8+2x^3) from (3x^3-4-3x)

2 answers:

konstantin123 [22]2 years ago

5 0

3x^3-4-3x-(-8+2x^3)
-> 3x^3-4-3x+8-2x^3
-> x^3-3x+4

Harman [31]2 years ago

3 0

$\to \sf(3x^3-4-3x) - (-8+2x^3)$

$\to \sf(3x^3-4-3x) + 8 - 2x^3$

$\to \sf3x^3-4-3x + 8 - 2x^3$

$\to \sf3x^3 - 2x^3-3x +4$

$\to \sf x^3-3x +4$

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(a) Point estimate = 7.10

(b) The critical value is 1.960

(c) Margin of error = 0.800

(d) Confidence Interval = (6.3, 7.9)

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Step-by-step explanation:

Given

$\bar x = 7.10$ -- sample mean

$\sigma=5$ --- sample standard deviation

$n = 150$ --- samples

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The sample mean can be used as the point estimate.

Hence, the point estimate is 7.10

Solving (b): The critical value

We have:

$CI = 90\%$ --- the confidence interval

Calculate the $\alpha$ level

$\alpha = 1 - CI$

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Solving (c): Margin of error

This is calculated as:

$E = z * \frac{\sigma}{\sqrt n}$

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$E = 1.960 * \frac{5}{12.25}$

$E = \frac{1.960 *5}{12.25}$

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Solving (d): The confidence interval

This is calculated as:

$CI = (\bar x - E, \bar x + E)$

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3 years ago

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Answer:

Step-by-step explanation:

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