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3 years ago

11

The distance between Earth and the Moon was determined by measuring the time it took for light waves from Earth to travel to the

Moon and back. Why was it not possible to use sound waves for this experiment?

1 answer:

julsineya [31]3 years ago

3 0

Answer: there is no sound in space

Explanation: there is no vacum in space for sound to travel, therfore no sound waves

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The half-life of iodine-131 is 8.04 days. It’s decay constant equals

Svetllana [295]

Answer:

Explanation:

we know that half life of an element is

T=0.693/λ

where λ is decay constant in order to find decay constant

λ=0.693/T

λ=0.693/8.04

λ=0.086

7 0

3 years ago

stephen buys a new moped . he travels 4km south and then 6km east. how far does he need to go to get back where he started??

stiks02 [169]

Answer:

My answer is 7.2 km

Explanation:

When Stephen goes to the south and then to the east, he is drawing a right triangle, where the 4 km and 6 km sides are the cathetus of a right triangle.

Then we use the Pithagorean theorem to solve this problem. We need to find the hypotenuse.

c² = a² + b²

c² = 4² + 6²

c² = 16 + 36

c² = 52

c = 7.2 km

7 0

3 years ago

Astronomers use many different pieces of equipment to study space: optical telescopes on Earth, space telescopes, and space prob

Kobotan [32]

Then it would be C if D has been eliminated

8 0

3 years ago

Read 2 more answers

A velocity selector in a mass spectrometer uses an electric field of 4.4 x 105 V/m. What magnetic field strength (in Tesla) is n

Brut [27]

Answer:

B = 9.16 10⁻² T

Explanation:

The speed selector is a configuration where the electric and magnetic force has the opposite direction, which for a specific speed cancel

q v B = q E

v = E / B

B = E / v

Let's calculate

B = 4.4 10⁵ / 4.8 10⁶

B = 9.16 10⁻² T

5 0

4 years ago

A drag racer starts her car from rest and accelerates at 5.5 m/s2 for the entire distance of 523 m. How long did it take the car

ANEK [815]

Answer:

t = 13.7 s or t = 14 s with proper significant figures

Explanation:

The initial speed is 0 m/s since the car starts from rest, acceleration is 5.5 m/s2 and distance is 523 m.

Since we have initial speed, acceleration and distance we can use the following formula to find the time. We can now use algebra to work out our answer.

d = vt + $\frac{1}{2}$ at²

523 = (0)t + ( $\frac{1}{2}$ )(5.5)t²

523 = 2.8t²

186.8 = t²

13.7 s = t

(t = 14 s with proper significant figures)

3 0

3 years ago