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Elden [556K]
3 years ago
11

43

Physics
1 answer:
soldier1979 [14.2K]3 years ago
6 0

Answer:

c quarks nuenuertons d protonsa

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melomori [17]

I believe the answer is purple

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3 years ago
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The sound intensity a distance d1 = 15.0 m from a chain saw is 0.260 W/m2. What is the sound intensity a distance d2 = 27.0 m fr
bagirrra123 [75]

Answer:

0.08024 W/m²

Explanation:

P = Power

d_1 = Distance = 15 m

I_1 = Intensity at 15 m = 0.26 W/m²

d_2 = Distance = 27 m

I_1 = Intensity at 27 m

Sound intensity is given by

I=\frac{P}{4\pi d^2}

\\\Rightarrow I\propto \frac{1}{d^2}

So, we have the relation

\frac{I_1}{I_2}=\frac{d_2^2}{d_1^2}\\\Rightarrow I_2=\frac{d_1^2\times I_1}{d_2^2}\\\Rightarrow I_2=\frac{15^2\times 0.26}{27^2}\\\Rightarrow I_2=0.08024\ W/m^2

The sound intensity at the given distance is 0.08024 W/m²

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4 years ago
I need help with this​
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4 years ago
V1= 25 L<br> T1= 200 degrees Kelvin<br> V2= 30 L<br> T2= ? degrees Kelvin
IceJOKER [234]
25x = 200*30
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3 years ago
The mechanical advantage shown in the image is?
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Mechanical Advantage= output force/input force. So, 156/52=3. You're MA is 3.
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