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Elden [556K]
3 years ago
11

43

Physics
1 answer:
soldier1979 [14.2K]3 years ago
6 0

Answer:

c quarks nuenuertons d protonsa

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What is mean by the value of universal gravitional constant is 6.67×10^-11​
aev [14]

Answer:

According to the gravitational law of Isaac Newton, "the gravitational force between any two objects is proportional to the product of the objects’ masses and inversely proportional to the square of the separation between their centers".

Therefore gravitational constant is the proportionality constant used in Newton’s Law of Universal Gravitation, and is commonly denoted by G. It is expressed as:

                                                 F= Gm1m2/r2

Another scientist Cavendish was able to measure the gravitational force and the value of the proportionality constant. It is expressed as G = 6.673×10-11 N m2 kg-2.

8 0
3 years ago
a student needs to calculate the density of some liquid. the student knows that density is equal to mass divided by volume. Name
Advocard [28]

The student can measure a liquid's volume by using a graduated cylinder, or a beaker. Mass can be measured by first weighing an empty container on a scale, and then by adding the liquid to the container and weighing it again.

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4 years ago
Read 2 more answers
What type of bond is shown in the figure?
ladessa [460]

Answer:

ionic

Explanation:

6 0
3 years ago
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Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates fo
eduard

Answer:

Vf₂ = 2 Vf₁

It shows that final speed of Joe is twice the final speed of Jim.

Explanation:

First, we analyze the final speed of Jim by using first equation of motion:

Vf₁ = Vi + at

where,

Vf₁ = final speed of Jim

Vi = initial speed of Jim = 0 m/s

a = acceleration of Jim

t = time of acceleration for Jim

Therefore,

Vf₁ = at   ---------------- equation (1)

Now, we see the final speed of Joe. For Joe the parameters will become:

Vf = Vf₂

Vi = 0 m/s

a = a

t = 2t

Therefore,

Vf₂ = 2at  

using equation (1):

<u>Vf₂ = 2 Vf₁</u>

<u>It shows that final speed of Joe is twice the final speed of Jim.</u>

3 0
3 years ago
A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o
dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is  m_1 = 81.14 \ kg

Explanation:

From the question we are told that

   Mass of the first block is  m_1 = 100 \  kg

   The height is  s =  1.0 \  m

   The time it takes it is  t = 1.40 \  s

 Generally from kinematic equation

       s =  ut + \frac{1}{2} at^2

Here u  is the initial velocity which zero given that it was at rest initially

So

     s =  0 * t + \frac{1}{2} at^2

=>  s =   \frac{1}{2} at^2

=> 1 =   \frac{1}{2}*  a *  (1.40 )^2

=>  a = 1.0204 \  m/s^2

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is  mathematically represented as

      mg - T = ma

=>   T  =  m g - ma

=>   T  =  m(g - a)

=>   T  =  877.96 \  N

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is  mathematically represented as  

     T - m_1g  =  m_1 a

=>   877.96  =  m_1 (a + g)

=>   877.96  =  m_1 (1.0204  + 9.8 )

=>   m_1 = 81.14 \ kg

5 0
3 years ago
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