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Drupady [299]
3 years ago
6

What is electricity?​

Physics
2 answers:
const2013 [10]3 years ago
4 0

Explanation:

electricity is the flow of electrical power or charge

777dan777 [17]3 years ago
3 0

Explanation:

the flow of current is called electricity

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At room temperature of the 92 naturally occurring elements, state the number that are:
Romashka-Z-Leto [24]
At room temperature of the 92 naturally occurring elements, 11 are gases, 2 are liquids and the rest are solids. The 11 gases include: hydrogen, oxygen, chlorine, fluorine, iodine, nitrogen, xenon, neon, helium, krypton, and argon. The 2 liquids are bromine and mercury. 
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4 years ago
Unit of energy density of electric field is a) NC-3 b) JC-3 c) Jm-3 d)JF
erik [133]

Answer:

the answer is c

8 0
4 years ago
Read 2 more answers
A cylinder rotating about its axis with a constant angular acceleration of 1.6 rad/s2 starts from rest at t = 0. At the instant
OverLord2011 [107]

Answer:

The magnitude of the total linear acceleration is 0.27 m/s²

b. 0.27 m/s²

Explanation:

The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.

The radial acceleration is given by;

a_t = ar

where;

a is the angular acceleration and

r is the radius of the circular path

a_t = ar\\\\a_t = 1.6 *0.13\\\\a_t = 0.208 \ m/s^2

Determine time of the rotation;

\theta = \frac{1}{2} at^2\\\\0.4 = \frac{1}{2} (1.6)t^2\\\\t^2 = 0.5\\\\t = \sqrt{0.5} \\\\t = 0.707 \ s\\\\

Determine angular velocity

ω = at

ω = 1.6 x 0.707

ω = 1.131 rad/s

Now, determine the radial acceleration

a_r = \omega ^2r\\\\a_r = 1.131^2 (0.13)\\\\a_r = 0.166 \ m/s^2

The magnitude of total linear acceleration is given by;

a = \sqrt{a_t^2 + a_r^2} \\\\a = \sqrt{0.208^2 + 0.166^2} \\\\a = 0.266 \ m/s^2\\\\a = 0.27  \ m/s^2

Therefore, the magnitude of the total linear acceleration is 0.27 m/s²

b. 0.27 m/s²

5 0
3 years ago
When particles spread out due to an increase of thermal energy this is called? ​
Lelechka [254]

This sounds like thermal expansion.

5 0
3 years ago
The length of the assembly decreases by 0.006 in. when an axial a- force is applied by means of rigid end plates. Determine
Triss [41]

Answer:

(a) The magnitude of the applied force is (0.0001524k) Newton

(b) Corresponding stress in the steel core = (0.0001524k/area) Newton per meter square

Explanation:

(a) From Hookes law of elasticity,

Force applied = force constant (k) × compression

compression = 0.006 in = 0.006 × 0.0254 = 0.0001524 meter

Force applied = k × 0.0001524 = (0.0001524k) Newton

(b) Stress = Force applied (Newton)/area of steel core (meter square) = (0.0001524k/area) Newton per meter square

6 0
3 years ago
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