Answer:
A minimum of 10 dimes and 11 quarters is what Alexandra will have
Step-by-step explanation:
Let
d = number of dimes
q = number of quarters
Since she has 21 coins altogether,
d + q = 21------------------------equation 1
- If these coins are worth $3.75 then
0.10 x d + 0.25 x q = 3.75
- which is 0.10d +.25q =3.75
--------------------------equation 2
where $.10 is the value of one dime and $.25 is the value of one quarter
make d the subject of formula from equation 1 d = 21 -q----------equation 3
insert it in equation 2
0.10d +0.25q =3.75
0.10(21-q) + 0.25q = 3.75
0.1(21)-0.1q+0.25q=3.75
2.1 +0.15q = 3.75
0.15q = 3.75-2.1 = 1.65
q = 1.65/0.15 =165/15 =11
- since we have the value of q insert in equation 3
d = 21 - q
d = 21-11
d = 10
Alexandra has 10 dimes and 11 quarters.
from my calculation i can see that the a minimum of 10 dimes and 11 quarters is what Alexandra will have
Answer:
Step-by-step explanation:
- Jelly beans weight = 10 pounds
- Each bag = 2/3 pound
<u>Number of bags required:</u>
- 10 ÷ 2/3 = 10 × 3/2 = 30/2 = 15 bags
Answer:
x = 1
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4x−
5
5
=3
4x+−1=3
4x−1=3
Step 2: Add 1 to both sides.
4x−1+1=3+1
4x=4
Step 3: Divide both sides by 4.
4x
4
=
4
4
x=1
Answer:
(2/5)*b+1 = -11 // + 11
(2/5)*b+1+11 = 0
2/5*b+12 = 0 // - 12
2/5*b = -12 // : 2/5
b = -12/2/5
b = -30
b = -30
Step-by-step explanation:
hope this helped :)
horizontal shift: 3 units to the left
vertical shift: 4 units down
