The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Extend means to increase, add length to it, ADD.
2.826
+ 1.46
--------------
4.286
Answer:
x = 14 units
Step-by-step explanation:
- Distance of both the chords from the center of the circle is 9 units.
- -> Both the chords are equal. (Chords equidistant from the center of the circle are equal)
- Perpendicular drawn from the center of the circle bisects the chord.
- -> Measure of one chord = 7 + 7 = 14 unit
- -> Measure of the other chord = 14 units
Answer: The answer would be 3.91666666667
