Answer:
measure of angle F= 109 degrees
Step-by-step explanation:
I believe by m you are solving for angle F. So, angle H =71 degrees. GF and HI are parallel. In order to find angle G, Take the supplementary of 71 degrees, so 180-71 = angle G =109 degrees. Because GH and FI are congruent, the angles should be same across the shape, so angle I 71 degrees. Quadrilateral has a total of 360 degrees, so, 360-71-109-71=109 degrees. In general, angke G would equal angle F because of the trapezoid properties that take place when both bases are parallel and two of the sides are congruent, the trapezoid is an isosceles trapezoid
SOLUTION
Given the question in the image, the following are the solution steps to verify the identity
STEP 1: Write the given identity

STEP 2: Verify the identity

The verification of the identity is as seen above.
Answer:
22 is the range for the data set.
<h3>stay safe healthy and happy.</h3>
Answer:
pretty easy ヽ(・∀・)ノ
Step-by-step explanation:
When you are dividing by a decimal, you have to move the decimal to the right however many places to make it a whole number. In this case if you move the decimal 1 place to the right (that means multiplying by 10) .8 becomes 8. However many places you move the decimal, you have to do the same for the other number. In this case 30.0 becomes 300. Now the problem becomes 300 ÷ 8.