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JulsSmile [24]
3 years ago
13

1. Solve the system of equations algebraically.

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0
Hello,
Please, see the attached files.
Thanks.

Andrew [12]3 years ago
4 0
1. We can double the second equation to get: 2x - 6y = 6; and then add the equations together to get -y = 4, y = -4. We plug y in to get x - 3(-4) = 3, x = 15. The answer would be (15, -4)
2. We can subtract the two equations to eliminate y and get 2x = 12, x = 6. We can plug x in to the second equation to get 9 + 3y = 18, and 3y = 9, so y = 3. The answer would be (6, 3)
3. We add the first two equations to get 8x - 5y = -34, and then subtract the last two equations to get 3x - 2y = -13. We multiply the first by 2, and the second by 5, and then add them together. We get x = -3. We plug the x-value into the second equation to get -9 - 2y = -13, so y = 2. We plug both values into the third equation to get -9 - 2 - z = -6. -z = 5, z = -5.
---
Hope this helps!
==jding713==
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Using the chart above, find the total amount and amount of interest paid in the following compound interest problems.
gizmo_the_mogwai [7]

Answer:

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Step by Step Explanation:

We can see from the table that the factor that we need to multiply with 900 in order to get amount for compounded annually is 1.7908477. Therefore, our total amount is 1.7908477*900 = 1611.76 and interest earned is 1611.76-900 = 711.76.

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3 years ago
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Alik [6]
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49:21
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Hope this helps!

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3 years ago
Read 2 more answers
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Step-by-step explanation:

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D=R-{5}

4 0
3 years ago
Read 2 more answers
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