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Otrada [13]
3 years ago
5

Nine less than a number is no more than 8 and is no less than 3

Mathematics
1 answer:
frozen [14]3 years ago
7 0

9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1

9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6

So the number is between 1 and 6, notation 1 < x < 6

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Need help ASAP!!!!!
svetlana [45]

Answer:

cos 45 degree = A/H

cos 45 degree =  2 square root 2 / x

x = 2 square root 2 / cos 45 degree

x = 4

Sin 45 degree = O/H

Sin 45 degree = y/ 4

4 x Sin 45 degree = y

y = 2.83

or

we could use tan

tan 45 degree = O/A

tan 45 degree = y / 2 square root 2

2 square root 2 x tan 45 degree = y

y = 2.83

i hope this would elp a little bit.

3 0
3 years ago
A liquid storage container is being filled at a constant rate. The container is being filled at a rate of 1/3 gallon per 1/4 min
denpristay [2]
1/4 x 16 = 4 min
 so 
1/3 x 16 = 16/3
8 0
3 years ago
Read 2 more answers
Need help with this
sveta [45]
5 is in the ones place. 6 is in the hundredths place. 9 is in the ten-thousandths place.
5 0
3 years ago
Read 2 more answers
Find the average of 27 and 45
Romashka [77]
Average is the total of the numbers divided by the amount of numbers.
\frac{27+45}{2}
\frac{72}{2}
36 is the answer.
3 0
3 years ago
Read 2 more answers
Consider the function . find the vertical asymptote(s) of f(x). x = 0, –9 x = –9 x = 0, 9 x = 9
kondaur [170]

The vertical asymptote of f(x) is (A) x = 0, –9.

<h3>What is a function?</h3>
  • A function is an expression, rule, or law in mathematics that describes a relationship between one variable (the independent variable) and another variable (the dependent variable).
  • Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.

To find the vertical asymptote of f(x):

The vertical asymptotes of a function are the zeroes of the denominator of a rational function

The function is given as: f(x) = \frac{(x-9)}{(x^{3} -81x)}

Set the denominator to 0:

  • x^{3} -81x=0

Factor out x:

  • x(x^{2} -81)=0

Express 81 as 9^2:

  • x(x^{2} -9^{2} )=0

Express the difference between the two squares:

  • x(x-9)(x+9)

Split, x=0 or x=-9 or x+9=0.

Solve for x:

  • x=0\\ or x=-9 or x+9=0.

Therefore, the vertical asymptote of f(x) is (A) x = 0, –9.

(See attachment for the graph of f(x))

Know more about functions here:

brainly.com/question/6561461

#SPJ4

The complete question is given below:

Consider the function f(x)=(x-9)/(x^3-81x) . find the vertical asymptote(s) of f(x).

A) x = 0, –9

B) x = –9

C) x = 0, 9

D) x = 9

3 0
2 years ago
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