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Otrada [13]
3 years ago
5

Nine less than a number is no more than 8 and is no less than 3

Mathematics
1 answer:
frozen [14]3 years ago
7 0

9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1

9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6

So the number is between 1 and 6, notation 1 < x < 6

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X-13 &lt; -11<br> pls help me solve
PSYCHO15rus [73]
So -13 + -11 = 23 so x equals 23
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3 years ago
PLEASE PLEASE PLEASE HELP ME!
Ghella [55]

Answer:

V of the solid = 40 in³

Step-by-step explanation:

volume of the first rectangular (on left)

l*w*h = 2*4*2=16 in³

volume of the rectangular (on the right)

l*w*h = 2*2*6=24 in³

V1+V2 = 16 +24=40 in ³

7 0
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The x-axis and y-axis are two lines that create the coordinate plane. The x-axis is a horizontal line and the y-axis is a vertic
Stella [2.4K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Fifth-grade problem again (yayyyy)
marishachu [46]

Answer:

1 1/5

Step-by-step explanation:

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4 0
3 years ago
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How to solve using substitution<br> y=3/4X+5<br> 4x-3y=-1
Pachacha [2.7K]
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5

Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:

4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)

Let 's now solve the system   

4y=3x + 20
4x-3y=-1

We are to solve this system using subtraction.  To accomplish this, multiply the first equation by 3 and the second equation by 4.  Here's what happens:

12y = 9x + 60  (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)

Then we have 

 12y = 9x + 60
-12y =-16x - 4

If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x:  7x = 56; x=8

We were given equations   
</span><span>y=3/4X+5
4x-3y=-1

We can subst. x=8 into either of these eqn's to find y.  Let's try the first one:

y = (3/4)(8)+5 = 6+5=11

Then x=8 and y=11.

You should check this result.  Subst. x=8 and y=11 into the second given equation.  Is this equation now true?</span>
5 0
3 years ago
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