Ask question

Ask question

All categories

skelet666 [1.2K]

3 years ago

5

find the set of five items of data that has a range of 9, a mean of 11, a meadian of 12, and a mode of 15.

1 answer:

ValentinkaMS [17]3 years ago

3 0

Here's what I've done:

Represent the set of 5 items by {a,b,c,d,e}. Assume that these items have already been arranged in ascending order.

The middle item, c, has the value 12.

Since "mode" means "most frequently appearing item," let's assume that d and e are both 15.

If the range is 9, we could then write 15-9 = 6, meaning that a = 6.

Then we have {6,b,12,15,15}

To find b, sum up {6,b,12,15,15}, equate the result to 11, and solve for b.

You might be interested in

fred is playing tennis fo every 2 of his serves that land in 4 serves land out if he hit 26 serves in how many serves landed out

ki77a [65]

Answer:

52 serves landed out

Explanation:

If you divide the number of serves in by 2 ( number that he lands in for every 6 serves) and then multiply by 4 ( number that land out for every 6 serves), you get 52 serves out.

3 0

3 years ago

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute <em>h</em> in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for <em>d</em>, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago

After observing this pattern, Felipe made a conjecture for the next number in the pattern.

lys-0071 [83]

The next number in this pattern should be A)28

3 0

3 years ago

Read 2 more answers

Convert x-y=3 and x-2y=3 into slope intercept form.

rodikova [14]

Y=x-3 and Y=1/2x-3/2 and that is ur answer

5 0

3 years ago

Enrico is designing a rectangular board for a game. He wants the ratio of the length to the

Aleks [24]

Answer:

$A(x)=\frac{6}{5}x^2$

Step-by-step explanation:

Let

y ----> the length of the board

x ----> the width of the board

we know that

$\frac{y}{x}=\frac{6}{5}$

$y=\frac{6}{5}x$ ----> equation A

The area of the board is

$A=xy$ ----> equation B

substitute equation A in equation B

$A=x(\frac{6}{5}x)$

$A(x)=\frac{6}{5}x^2$

6 0

4 years ago