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Vinvika [58]
3 years ago
15

How can you decide whether the domain of a function is discrete or continuous? Describe two real-life examples of functions: one

with a discrete domain and one with a continuous domain.
Mathematics
1 answer:
mart [117]3 years ago
6 0

Answer: Continuous, Domain is {0<~x

Step-by-step explanation:

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You accumulated a balance of $2,300 on your credit card that carries an interest rate of 17%. You can't afford to pay the $2,300
4vir4ik [10]

Answer:

$1,591.67

Step-by-step explanation:

The computation of the balance after 5 years is shown below:

Given that

Accumulated Balance on Credit Card = P = $2,300

r = Monthly interest amount = 17% ÷ 12 = 1.41666667%

M = Minimum payment = 2%

Now  

Balance on Credit Card after t year = P × (1+r) ×(1-M)

= $2,300 × (1+1.41666667%)^t × (1 - 2%)^t

= $2,300 × (0.993883337)^t

SO,

Balance on Credit Card after 5 years is

= $2,300 × (0.993883337)^60

= $2,300 × 0.692029437

= $1,591.66771

= $1,591.67

8 0
3 years ago
1) Mister Smith wants to put a small fence around his garden. A store sells three feet sections of fence at cost of $5.49 per se
Gelneren [198K]
1. Mister Smith spends $145 total. The number of sections is$ 145/$ 5.49 = 26.41 ~ 27 sectionsThe length of the fence is27 (3) = 81 feet
2. Let x be the number of students in each class. The inequality is0.5x + 4 > 7.25
3. D) 38<=B<=48 
4. C) 6<=M<=85 
5. B) M+H<=10,4M+7H<90 
5 0
3 years ago
Sarah and Paula are flipping coins. During each round, each one flips a fair coin and then they compare their results. What is t
MrRissso [65]

Answer:

1/3

Step-by-step explanation:

The rounds that give two heads can be neglected.

Looking at the first round that gives at least one tail let T

denotes the number of tails is that round

P(T=2\mid T\geq1)=\frac{P(T=2)}{P(T\geq1)}=\frac{1/4}{3/4}=\frac13

6 0
3 years ago
The opposite corners of a quadrilateral are right angles. What kind of quadrilateral is this figure?
never [62]

Answer:

Send a picture for a full answer.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Simplify completely 25 w to the sixth power over 10 w to the third power divided by 30 w squared over 5 w.
Amiraneli [1.4K]
<span>25 w to the sixth power over 10 w to the third power divided by 30 w squared over 5 w.

25w</span>⁶ / 10w³  ÷ 30w² / 5w

Get the reciprocal of the 2nd fraction and multiply it with the 1st fraction

25w⁶ / 10w³   * 5w / 30w² → 25w⁶ * 5w / 10w³ * 30w² = 125w⁷ / 300w⁵ 

*When you multiply exponents with the same base, you simply add them.
w⁶ * w = w⁶⁺¹ = w⁷
w³ * w² = w³⁺² = w⁵

Cancel out w⁵
<span>125w⁷ / 300w5 </span>= 125w² / 300

Simplify the constant:
125 / 25 = 5
300 / 25 = 12

5w² / 12    is the simplified form of the given equation. 
7 0
3 years ago
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