Answer with Step-by-step explanation:
We are given that n and m are two integers
We have to prove that if n-m is even , then 
is also even.
We know that sum of two odd numbers is even.Sum of an odd number and even number is odd.
Product of an odd number and even number is even.
Case 1.Suppose m and n are both even n=4 , m=2
Case 2.Suppose m odd and n odd
n=9,m=5
Hence, proved.
Answer:
(3x^2-5x-5)/(x^2+x) <--- answer
Step-by-step explanation:
3x/(x+1) - 5/x = (3x^2 - 5(x+1) )/[ x(x+1) ]
= (3x^2 - 5x - 5)/(x^2 + x)
Answer:
The median is: 9
The mode is: 9,10
The mean is: 8
Step-by-step explanation:
Hope this helps!
The value of f(-3) is 5.
In order to find this answer, we are going to input -3 in for x (this is what the notation f(-3) means).
f(x)=| x-2 |
f(-3)=| -3 -2 |
f(-3)=| -5 |
Now we have to take the absolute value.
f(-3) = 5
