The answer to this problem is 1048$
Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Answer:
solution is ![\boxed{x=-1,x=-11}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D-1%2Cx%3D-11%7D)
Step-by-step explanation:
f(x)=2|x+6|-4
either x+6 is positive and then |x+6|=x+6
or it is negative and |x+6| = -(x+6)=-x-6
case 1: x>=-6
f(x)= 2x+12-4=2x+8
f(x)=6 <=> 2x+8=6 <=> 2x = 6-8=-2 <=> x = -1
case 2: x<=-6
f(x)=-2x-12-4=-2x-16
f(x)=6 <=> -2x-16=6 <=> 2x=-16-6 = -22 <=> x = -11
so to recap, the solutions are x=-1 and x=-11
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we know that
<u>Simple events</u> are those events where one experiment occurs at one time and it will have a single outcome.
Option 'A' says Getting doubles on a roll of two dice : It has more than one outcome.
i.e. (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).
Similarly, In option 'C' and 'D' both have more than one outcomes.
But Option 'B' says Getting a 4 on a roll of one die : It has single outcome and its probability will be ![\dfrac{1}{6}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B6%7D)
Hence, Option 'B' is simple event.
Therefore, Option 'b' is correct.
The answer is transformation :)