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Cloud [144]
3 years ago
15

How can you tell if a fraction is a perfect square?

Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answers: A fraction is a perfect square if it's reduced version (of an improper fraction if the number is greater than 1) has both numerator and denominator numbers that are perfect squares. IE: 25/36 is a perfect square because both 25 and 36 are perfect squares.

Step-by-step explanation:

So for example 5/25 is a perfect square but 2/5 wouldn't be a perfect square.

Tell me if this helped you

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a rectangular gift box is 10 inches long, 7 inches wide, 1.25 inches high, and had a surface area of 182.5 square inches. gift w
nalin [4]
1) 2 * (10 * 7 + 7 * 1,25 + 10 * 1,25) = 2 * (70 + 8,75 + 12,5) = 2 * 91,25 = 182,5 square inches - a surface area
2) 182,5 * 0,012 = <span>$</span>2,19 - answer.
6 0
2 years ago
3 more than w divided by 7 is 9
svlad2 [7]
3 + [_] ÷ 7 = 9

[_] ÷ 7 = 9 - 3

[_] = 6 x 7

[_] = 42

to check, just put 42 in the empty place and solve
5 0
2 years ago
Nathan is going to invest in an account paying an interest rate of 1.9% compounded continuously. How much would Nathan need to i
Sliva [168]

Answer:

223 (rounded to closest one) actual answer would be 222.91479275

Step-by-step explanation:

use formula A=Pe^nt

$280 = Pe^0.019(12)

$280 = Pe^0.228, then evaluate the solution by isolating the variable and dividing each side by the factors which don't contain the variable.

P = 222.91479275

3 0
2 years ago
Abby bought an 8 pound bag of doog food for $7.40. How much does the bag cost per pound? (round to the nearest hundreth)
Sergio039 [100]

Answer:

a

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Consider w=sqrrt2/2(cos(225°) + isin(225°)) and z = 1(cos(60°) + isin(60°)). What is w+ z expressed in rectangular form?
SVETLANKA909090 [29]

Answer:

Option (3)

Step-by-step explanation:

w = \frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]

Since, cos(225) = cos(180 + 45)

                          = -cos(45) [Since, cos(180 + θ) = -cosθ]

                          = -\frac{\sqrt{2}}{2}

sin(225) = sin(180 + 45)

             = -sin(45)

             = -\frac{\sqrt{2}}{2}

Therefore, w = \frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]

                      = -\frac{2}{4}(1+i)

                      = -\frac{1}{2}(1+i)

z = 1[cos(60) + i(sin(60)]

  = [\frac{1}{2}+i(\frac{\sqrt{3}}{2})

  = \frac{1}{2}(1+i\sqrt{3})

Now (w + z) = -\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})

                   = -\frac{1}{2}-\frac{i}{2}+\frac{1}{2}+i\frac{\sqrt{3}}{2}

                   = \frac{(i\sqrt{3}-i)}{2}

                   = \frac{(\sqrt{3}-1)i}{2}

Therefore, Option (3) will be the correct option.

3 0
3 years ago
Read 2 more answers
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