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3 years ago

Choose the two equations you would use to solve the absolute value equation below. Then solve the two equations.

Mathematics

1 answer:

sukhopar [10]3 years ago

6 0

$|x+5|=55\\\\x+5=55\ \vee\ x+5=-55\\\\x=55-5\ \vee\ x=-55-5\\\\x=50\ \vee\ x=-60$

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Find the sun and express it in simplest form.(-3s-4c+1)+(-3s+3c)

DiKsa [7]

Answer:

-6s-c+1

Step-by-step explanation:

(-3s-4c+1)+(-3s+3c)

We have been given the above expression. To find the sum, we simply collect the like terms and combine them;

(-3s-4c+1)+(-3s+3c) = -3s + -3s -4c + 3c + 1

-3s + -3s -4c + 3c + 1 = -3s - 3s + 3c - 4c + 1

-3s - 3s + 3c - 4c + 1 = -6s - c + 1

Therefore;

(-3s-4c+1)+(-3s+3c) = -6s-c+1

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3 years ago

Which are factors of x2 – 4x – 5? Select two options. (x – 5) (x – 4) (x – 2) (x 1) (x 5).

Greeley [361]

Answer:

(x - 5) (x + 1)

Step-by-step explanation:

x² - 4x - 5

= x² + x - 5x - 5

= x(x + 1) - 5(x + 1)

= (x - 5) (x + 1)

5 0

2 years ago

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3 years ago

A convenience store sells a coffee mug that comes

madreJ [45]

Answer:

The cost of the mug is of $6.50.

Step-by-step explanation:

The cost of the mug and r refills is given by the following equation:

$C(r) = 2.3r + 6.5$

Cost of the mug:

The cost of the mug is found when no refills are bought, that is, C when $r = 0$ , which is $C(0)$

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The cost of the mug is of $6.50.

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3 years ago

How are the following three expressions different from each other, if needed they are? Do not just state the value of each but e

Advocard [28]

Answer:

2 and 3 are same since in both the cases we need to square 2 only not the negative 1 in it

1 is not same to 2 and 3 since in 1 we need to square 2 and negative 1 in it also.

Step-by-step explanation:

We are given the three expressions different from each other

We are supposed to find what may be same or different.

1) $(-2)^2$

$\Rightarrow (-1)^2 \times (2)^2\\\Rightarrow -1 \times -1 \times 2 \times 2 \\\Rightarrow 4$

2) $-2^2$

$\Rightarrow -1 \times 2^2\\\Rightarrow -1 \times 2 \times 2 \\\Rightarrow -4$

3) $-(2)^2$

$\Rightarrow -1 \times (2)^2\\\Rightarrow -1 \times 2 \times 2 \\\Rightarrow -4$

Now 2 and 3 are same since in both the cases we need to square 2 only not the negative 1 in it

1 is not same to 2 and 3 since in 1 we need to square 2 and negative 1 in it also.

3 0

3 years ago