Answer:
bby there's no graph you forgot to add it
Step-by-step explanation:
- comment if you did the question over :)
Answer:
intrest equation
I/PT = R
$680 / $72,000 x 12 years = R
$680 / $864,000 = R
7.8703 = R
or rounded 8%
Step-by-step explanation:
Answer: (1) Measure of angle K = x degrees
(12) Measure of angle L = (5x) degrees
(3) Measure of angle k + Measure of angle L + Measure of angle N = 180 degrees
Step-by-step explanation: First of all, what we have is a triangle, and one of the properties of a triangle is all three angles add up to 180 degrees. This simply means that the addition of angles K and L and N would be equal to 180 degrees.
The question states that angle K is represented as x degrees, and angle L is 5 times the measure of angle K. Therefore, if K is x degrees, then L is 5 times x, which becomes 5x degrees. Also, angle N is given as 16 degrees less than 8 times the measure of angle K (x degrees). Eight times the measure of angle K is given as 8x. Sixteen degrees less than 8x would now become, 8x - 16 (degrees). Therefore, the angles have been derived as;
Angle K = x degrees
Angle L = 5x degrees
Angle N = 8x - 16 degrees
Having known that one of the properties of any triangle is all angles adding up to 180 degrees, we can now derive the following equation;
x + 5x + 8x - 16 = 180
14 x - 16 = 180
Add 16 to both sides of the equation
14x = 196
Divide both sides of the equation by 14
x = 14
Therefore, angle K = 14 degrees (x), angle L = 70 degrees (5x) and angle N = 96 degrees (8x - 16)
*14 + 70 + 96 = 180*
This is a hypergeometric distribution problem.
Population (N=50=W+B) is divided into two classes, W (W=20) and B (B=30).
We calculate the probability of choosing w (w=2) white and b (b=5) black marbles.
Hypergeometric probability gives
P(W,B,w,b)=C(W,w)C(B,b)/(C(W+B,w+b)
where
C(n,r)=n!/(r!(n-r)!) the number of combinations of choosing r out of n objects.
Here
P(20,30,2,5)
=C(20,2)C(30,5)/(20+30, 2+5)
=190*142506/99884400
=0.2710
Alternatively, doing the combinatorics way:
#of ways to choose 2 from 20 =C(20,2)
#of ways to choose 5 from 30=C(30,5)
total #of ways = C(50,7)
P(20,30,2,5)=C(20,2)*C(30,5)/C(50,7)
=0.2710
as before.