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ollegr [7]
2 years ago
8

Plzzz help I suck at math ....

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
6 0
The answer is the last choose 1
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Guys i need your HELP ASAP​
ivanzaharov [21]
To solve this, you’ll first need to solve for their slopes.

The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3

We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3

The equation you get it y = 1/3x + b.

Now you will need to solve for b by substituting in the first ordered pair of line R.

2 = 1/3(1) + b.

Once you solve for b, you should get 5/3 and y = 1/3x + 5/3

Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.

y = 1/3(10) + 5/3.

Your solution should be 5.

So your answer is: a = 5
8 0
3 years ago
Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me
8090 [49]

Answer:

The sum of the probabilities is greater than 100%; and the distribution is too uniform to be a normal distribution.

Step-by-step explanation:

The sum of the probabilities of a distribution should be 100%.  When you add the probabilities of this distribution together, you have

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This is more than 100%, which is a flaw with the results.

A normal distribution is a bell-shaped distribution.  Graphing the probabilities for this distribution, we would have a bar up to 22; a bar to 24; a bar to 21; a bar to 26; and bar to 28.

The bars would not create a bell-shaped curve; thus this is not a normal distribution.

3 0
3 years ago
Read 2 more answers
What is the value of x in the equation -6x = 5x+ 22?<br> -22<br> 0 -2<br> 02<br> O 22
Ivahew [28]

Answer:

x = -2

Step-by-step explanation:

Solve  -6x = 5x + 22

add 6x to both sides

0 = 6x + 5x + 22

0 = 11x + 22

11x = -22

x = -22/11

x = -2

3 0
3 years ago
Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
Is 3.67676767 a irrational number
Nikitich [7]
I’m pretty sure it’s irrational
3 0
3 years ago
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