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ollegr [7]
3 years ago
8

Plzzz help I suck at math ....

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0
The answer is the last choose 1
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I need to know this asap thanks
lisabon 2012 [21]
1. 1   7/8

wait a minute for me to answer number 2

7 0
3 years ago
A bottling company uses a filling machine to fill plastic bottles with cola. The bottles are supposed to contain 300 milliliters
PilotLPTM [1.2K]

Answer:

e. 0.0072

Step-by-step explanation:

We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .

 Let    Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  where, Xbar = mean contents of six randomly

                                                                     selected bottles

                                                          n = sample size i.e. 6    

So, Probability that the mean contents of six randomly selected bottles is less than 295 ml is given by, P(Xbar < 295)

 P(Xbar < 295) = P( \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{295 - 298}{\frac{3}{\sqrt{6} } } ) = P(Z < -2.45) = P(Z > 2.45)

Now, using z% score table we find that P(Z > 2.45) = 0.00715 ≈ 0.0072 .

Therefore, option e is correct .

7 0
3 years ago
I need heelp solving plzz
Nonamiya [84]

Answer:

The anser is 5 hop this helps sorry if it is wrong

Step-by-step explanation:

3 0
2 years ago
Simplify the radical expression 5√7+2√175
yanalaym [24]
5\sqrt{7} + 2\sqrt{175}=5\sqrt{7}+2\sqrt{25 \cdot 7}=5\sqrt{7}+ 2 \cdot \sqrt{25} \cdot \sqrt{7}= \\ \\ = 5\sqrt{7}+2 \cdot 5 \cdot \sqrt{7}=5\sqrt{7}+10\sqrt{7}=\boxed{15\sqrt{7}} \approx 39.69

remember about formula \sqrt{ab} = \sqrt{a} \cdot \sqrt{b}
5 0
3 years ago
Will give brainliest<br> Please help with problem, I don't understand it
Alex787 [66]

Answer:

111.375

Step-by-step explanation:

each triangle are equal to each other, it equals (b x h)/2

good luck and thanks for the brainliest!

6 0
2 years ago
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