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Basile [38]
2 years ago
12

You are riding a roller coaster when a shoe falls off your foot. The function y=300−16t2 represents the height y (in feet) of th

e shoe t seconds after it falls off your foot. The shoe lands on the top of an 11-foot-tall building. After how many seconds does the shoe hit the building?
Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
8 0

Answer:

Time to land on 11ft is 4.25 seconds

Step-by-step explanation:

Given

y = 300 - 16t^2

Required

Solve for t when height is 11ft

This implies that y = 11

So: substitute 11 for y in y = 300 - 16t^2

11 = 300 - 16t^2

Collect Like Terms

16t^2 = 300 - 11

16t^2 = 289

Express both sides as squares

4^2 * t^2 = 17^2

(4t)^2 = 17^2

Take square roots of both sides (ignore negative)

4t = 17

Solve for t

t = \frac{17}{4}

t = 4.25

Hence, time to land on 11ft is 4.25 seconds

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What is the solution to this equation pls pls pls<br><br> x(at the power of 2) = 6 + 9x
kati45 [8]

Answer:

The solution to the equation are x = 5.089  and    x = -0.589

Step-by-step explanation:

Given:

x(at the power of 2) = 6 + 9x

To Find:

The solution of the equation = ?

Solution:

The given equation can be written as  

=> 2x^2 = 6+9x

=>2x^2-6 -9x=0

=>2x^2-9x-6=0

Using the quadratic formula,

x = \frac{-b\pm \sqrt{(b^2 -4ac}}{2a}

where

a= 2

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Substituting these values,

x = \frac{-(-9)\pm \sqrt{(-9)^2 -4(2)(-6)}}{2(2)}

x = \frac{-(-9)\pm \sqrt{(81) -4(-12)}}{2(2)}

x = \frac{-(-9)\pm \sqrt{81+48}}{4}

x = \frac{-(-9)\pm \sqrt{129}}{4}

x = \frac{-(-9)\pm 11.357}{4}

x = \frac{9 \pm 11.357}{4}

x = \frac{9 + 11.357}{4}                        x = \frac{9 - 11.357}{4}

x = \frac{20.357}{4}                            x = \frac{-2.357}{4}  

x =5.089                                                           x =   -0.589

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The sum of two consecutive cube numbers is 341. Work out the two numbers. (2 marks)
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Answer:

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Step-by-step explanation:

you could use trail and error. So:

13+23=9

33+43=91

63+73=559

53+63=341

3 0
3 years ago
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