Find the value of r, if K is between J and L. if JK = 6r, KL = 3r, and JL = 27
2 answers:
You might be interested in
Composite figure is made up of 4 triangles and a square.
Area of Square = Length x Length
Area of Square = 12 x 12
Area of Square= 144 cm²
Area of triangle = 1/2 x base x height
Area of triangle = 1/2 x 12 x 8
Area of triangle = 48 cm²
Area of 4 Triangles = 48 x 4
Area of 4 Triangles = 192 cm²
Total Area = 144 + 192 = 336 cm²
Area of Square = Length x Length
Area of Square = 12 x 12
Area of Square= 144 cm²
Area of triangle = 1/2 x base x height
Area of triangle = 1/2 x 12 x 8
Area of triangle = 48 cm²
Area of 4 Triangles = 48 x 4
Area of 4 Triangles = 192 cm²
Total Area = 144 + 192 = 336 cm²
9514 1404 393
Answer:
- ∠QSR = 78°
- ∠SQR = 51°
Step-by-step explanation:
The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...
∠QSR = 2×∠QTR
∠QSR = 2×39°
∠QSR = 78°
__
Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...
∠QSR + 2(∠SQR) = 180°
78° + 2(∠SQR) = 180° . . . . fill in the value we know
2(∠SQR) = 102° . . . . . . . . . subtract 78°
∠SQR = 51° . . . . . . . . . . . . .divide by 2
