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Crank
3 years ago
10

I’ll give brainly

Mathematics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

possible

Step-by-step explanation:

3+7= 10

gogolik [260]3 years ago
3 0

Answer:

Possible

Step-by-step explanation:

The rule for triangle side lengths is that the two shortest sides must add up to the longest side so it is possible because

3+7 = 10

Two short sides = The longest side

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Which equation best models the fine schedule for overdue books? , where x is the cost in cents for a book that is y days overdue
earnstyle [38]

x is the independent variable, and in this scenario, the independent variable is the number of days overdue. So the best equation would be where x is the number of days overdue, and y is the cost in cents.


Example equation:



x = number of days overdue

y = cost in cents

z = total price

z = yx

4 0
3 years ago
Which term can be added to the list so that greatest common factor of the three terms is 12h^3? 36h^3 12h^6. 6h^3. 12h^2. 30h^4.
Juliette [100K]

Answer:

Last Option 48h^{5}.

Step-by-step explanation:

In this question we will do the factors of given two terms then we will do the common factors of all the terms given in answer to match with.

Common factors of 36h³ = 1×2×2×3×3×h×h×h

Common factors of 12h^{6} = 1×2×2×3×h×h×h×h×h×h

In these two terms greatest common factor Of these two terms is = 1×2×2×3×h×h×h = 12h³

Therefore the third term will be the number which has the greatest common factor = 12h³

So the given terms are

6h³ = 1×2×3×h×h×h

12h² = 1×2×2×3×h×h

30h^{4} = 1×2×3×5×h×h×h×h

48h^{5} = 1×2×2×2×2×3×h×h×h×h×h

Therefore the greatest common factor of the term which matches with 12h³ is 48h^{5}

3 0
3 years ago
Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an
Leya [2.2K]
Parameterize the lateral face T_1 of the cylinder by

\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v

where 0\le u\le2\pi and 0\le v\le3, and parameterize the disks T_2,T_3 as

\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)
\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)

where 0\le r\le2 and 0\le\theta\le2\pi.

The integral along the surface of the cylinder (with outward/positive orientation) is then

\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS
=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr
=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr
=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr
=136\pi
7 0
3 years ago
In quadrilateral ABCD, AD ∥ BC. Quadrilateral A B C D is shown. Sides A D and B C are parallel. The length of A D is 3 x + 7 and
oksian1 [2.3K]

Answer:

  31 units

Step-by-step explanation:

When the figure is a parallelogram, opposite sides have the same measure:

  AD = BC

  3x +7 = 5x -9 . . . . . . substitute given expressions

  16 = 2x . . . . . . . . . . . add 9-3x

  8 = x . . . . . . . . . . . . . divide by 2

Use this value of x in the expression for AD to find its required length:

  AD = 3(8) +7 = 24 +7

  AD = 31 . . . . units

The length of segment AD must be 31 units for ABCD to be a parallelogram.

8 0
3 years ago
Read 2 more answers
(2, -4) and (6,-10)<br> find the midpoint of the segment
asambeis [7]
The midpoint of the segment:
(4, 7)
x=4 y= -7
5 0
3 years ago
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