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Amiraneli [1.4K]
3 years ago
11

Help asap they are in order form top to bottom A B C D

Mathematics
1 answer:
Olin [163]3 years ago
3 0

Answer: The answer is B

Step-by-step explanation:

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Find the measure of the indicated angle to the nearest degree​
omeli [17]

\boxed{\sf sin\Theta=\dfrac{P}{H}}

\\ \sf\longmapsto sin\Theta=\dfrac{16}{26}

\\ \sf\longmapsto sin\Theta=\dfrac{8}{13}

\\ \sf\longmapsto sin\Theta=0.5

  • Convert to p/q form

\\ \sf\longmapsto sin\Theta=\dfrac{5}{10}

\\ \sf\longmapsto sin\Theta=\dfrac{1}{2}

\\ \sf\longmapsto sin\Theta=sin30

\\ \sf\longmapsto \Theta\approx30°

4 0
3 years ago
64, –48, 36, –27, ...<br><br> Which formula can be used to describe the sequence?
nordsb [41]

Answer:

\boxed{a_n \:  =  \: 64 \:  \times  \: ( -  \frac{3}{4} ) ^{n \:  -  \: 1} }

Step-by-step explanation:

  • We first compute the ratio of this geometric sequence.

r \:  =  \:  \frac{ - 48}{64}  \\  \\ r   \:  =  \:  \frac{36}{ - 48}  \\  \\  r \:  =  \:  \frac{ - 27}{36}

  • We simplify the fractions:

r \:  =  \:   -  \frac{3 }{4}   \\  \\ r   \:  =  \:   -  \frac{3 }{4}  \\  \\  r \:  =  \:    -  \frac{3 }{4}

  • We deduce that it is the common ratio because it is the same between each pair.

r \:  =  \:  -  \frac{3 }{4}

  • We use the first term and the common ratio to describe the equation:

a_1 \:  =  \: 64; \: r \:  =  \:  -  \frac{3 }{4}

<h3>We apply the data in this formula:</h3>

\boxed{a_n \:  =  \: a_1 \:   \times  \:  {r}^{ n \:  -  \: 1} }

_______________________

<h3>We apply:</h3>

\boxed {\bold{a_n \:  =  \: 64 \:   \times  \:  {( -  \frac{3}{4} )}^{ n \:  -  \: 1} }}

<u>Data</u>: The unknown "n" is the term you want

<h3><em><u>MissSpanish</u></em></h3>
4 0
2 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
For the graph shown to the right, find (a) AB to the nearest tenth and (b) the coordinates of the midpoint of AB.
Shkiper50 [21]
AB =

\sqrt{( {4 -  (- 2))}^{2}  +  {( - 5 + 3)}^{2} }  =  \sqrt{40}  = 6.3
The midpoint os segment AB =

(( \frac{ - 2 + 4}{2} ) = the \: x \: coordinate \: of \: the \: midpoint \\  \\ ( \frac{ - 3 - 5}{2})) = the \: y \: coordinate \: of \: the \: midpoint
The midpoint is:

(1,-4)
8 0
3 years ago
Meredith invested $5,500 into an account that earned 5% interest per year. When she cashed out the investment to use it as a dow
shtirl [24]

Answer:

Step-by-step explanation:

Using I = PRT/100

where P = The principal amount invested = $5500

R = Rate of Interest =5%

T = Time (in years)

I = Interest = $7,739.05 - $5500 = $2239.05

Substituting the above values in the formula

I = PRT/100 becomes

2239.05 = 7,739.05 * 5 * t / 100 -------- Multiply 100 to both sides

2239.05 * 100 = 100 * 7739.05 * 5 * t / 100

223905 = 7739.05 * 5 * t

223905 = 38695.25t

Divide both sides by 38695.25t

223905/38695.25 = t

5.786369 = t

T = 5.79 (approximated)

8 0
3 years ago
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