Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10 OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B

5 0

3 years ago

If roberto can build 1 house in 23 days, how many houses can he build in 207 days?

rusak2 [61]

He would be able to build 9 houses.

$\frac{207}{23} = 9$

3 0

4 years ago

The mean number of students in a classroom at school a is 32.5 and there are 25 classrooms. The mean number of students at schoo

Airida [17]

We have given three school there, School A, School B and School C.

We are going to use following formula.

Total number of student in a school = Mean of number of student × Number of classrooms.

School A

Mean of students in School A = 32.5.

Number of classroom in School A = 25.

Number of students in School A = Mean × number of classrooms = 32.5×25 = 812.5

School B

Mean of students in School B = 29.6.

Number of classroom in School B = 12.

Number of students in School B = Mean × number of classrooms = 29.6×12 = 355.2

School C

Mean of students in School C = 15.3.

Number of classroom in School C = 10.

Number of students in School C = Mean × number of classrooms = 15.3×10 = 153.

Total sum of number of classes in all schools = 25+12+10 = 47.

Total sum of all students in all schools = 812.5 +355.2 +153 = 1320.7 .

The mean number of students per classroom for all the schools combined =

$\frac{Total \ sum \ of \ all \ students \ in \ all \ schools}{Total \ sum \ of \ number \ of \ classes \ in \ all \ schools}$

= $\frac{1320.7}{47}$ = 28.1

The mean number of students per classroom for all the schools combined= 28.1

4 0

3 years ago

Convert the following mixed number into improper fraction and vice versa:70/48

Blababa [14]

$\frac{70}{40} \div \frac{2}{2}= \frac{35}{2} = 17 \frac{1}{2}$

5 0

4 years ago