Answer:
-2.85
Step-by-step explanation:
I looked it up tbh
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
As we strolled along the aged cobblestone walkway that meandered through the rose garden, we gazed at the array of fragrant, colorful blossoms.
Step-by-step explanation:
Mwah there lol <3
Hope it helps
Answer:
14.14
Step-by-step explanation:
You can find the value of x using the trig ratio Sine = opposite/hypotenuse.
The sin 45 = 10/x. Solve for x.
x= 10/ sin45
x = 10/0.707
x = 14.14
