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laiz [17]
3 years ago
13

What is the value of x in this equation? 5x + 12 = -18

Mathematics
2 answers:
adell [148]3 years ago
7 0

Answer:

<em>x</em><em> </em>= -6

Explanation:

First we collect like terms

<em>5x</em><em> </em><em>=</em><em> </em><em>-18</em><em> </em><em>-</em><em> </em><em>1</em><em>2</em>

<em>5x</em><em> </em><em>=</em><em> </em><em>-30</em><em> </em>

( because when both signs are the same we add them)

Then we decide both sides by five so that only x will remain

<em>5x</em><em> </em><em>/</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>-30</em><em> </em><em>/</em><em> </em><em>5</em>

<em>x</em><em> </em><em>=</em><em> </em><em>-6</em>

Thus, the value of <em>x</em><em> </em>is -6

siniylev [52]3 years ago
4 0

Answer:

x = −6

Step-by-step explanation:

I like to start off by simplifying the equation! Then, I use inverse operations to narrow it down until I reach the answer!

5x + 12= −18

5x + 12 <u>− 12</u>= −18 <u>− 12 </u>

5x = −30

5x<u>/5</u> = -30<u>/5</u>

<u>x = -6</u>

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torisob [31]

We have been given that :-

The length of a parasite in experiment A is 2.5 \times 10^{-3}

The length of a parasite in experiment B is 1.25 \times 10^{-4}

Let us write the the  length of the parasite in experiment A in the exponent of -3.

1.25 \times 10^{-4}= 0.125 \times 10^{-3}

Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.

The difference in the length is given by

2.5 \times 10^{-3} -0.125 \times 10^{-4}

=2.375 \times 10^{-3}

Therefore, the length of the parasite in experiment A is =2.375 \times 10^{-3} inches  greater than the length of the parasite in experiment B.

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3 years ago
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In triangle NQL, point S is the centroid, NS = (x + 10) feet, and SR = (x + 3) feet.
olya-2409 [2.1K]
Where R is the median between Q and L:

From my understanding of a triangle's centroid, it divides an angle bisector into parts of 2/3 and 1/3. In the given problem, these divisions are NS and SR. Therefore, twice SR would be equal to NS. From here, we can get the value of X, to solve for SR.

NS = 2SR
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If RSTU is a rhombus, find the measure of angle RUT.
Schach [20]

<u>Finding x:</u>

We know that the diagonals of a rhombus bisect its angles

So, since US is a diagonal of the given rhombus:

∠RUS = ∠TUS

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7x - 23 = 19                                [subtracting 3x from both sides]

7x = 42                                       [adding 23 on both sides]

x = 6                                           [dividing both sides by 7]

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We can see that:

∠RUT = ∠RUS + ∠TUS

<em>Since we are given the values of ∠RUS and ∠TUS:</em>

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