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Alenkinab [10]
2 years ago
14

If sec theta>0 and tan theta<0, the terminal side of angle theta must lie in​

Mathematics
2 answers:
kirill115 [55]2 years ago
8 0
Nandi ahsjej jeheh Helene
dem82 [27]2 years ago
3 0

Answer:

the last one

Step-by-step explanation:

super easy bro tell me if its right

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 I first found a common denominator and use it to rewrite each fraction. Then I, subtracted the whole numbers and fractions separately.
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What type of angles do the pairs of exterior angles of a triangle form?
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3 years ago
How do I get (tan^2(x)-sin^2(x))/tan(x) equal to (sin^2(x))/cot(x)
shepuryov [24]
LHS\\ \\ =\frac { \tan ^{ 2 }{ x-\sin ^{ 2 }{ x }  }  }{ \tan { x }  } \\ \\ =\frac { 1 }{ \tan { x }  } \left( \tan ^{ 2 }{ x-\sin ^{ 2 }{ x }  }  \right)

\\ \\ =\frac { \cos { x }  }{ \sin { x }  } \left( \frac { \sin ^{ 2 }{ x }  }{ \cos ^{ 2 }{ x }  } -\frac { \sin ^{ 2 }{ x\cos ^{ 2 }{ x }  }  }{ \cos ^{ 2 }{ x }  }  \right) \\ \\ =\frac { \cos { x }  }{ \sin { x }  } \left( \frac { \sin ^{ 2 }{ x-\sin ^{ 2 }{ x\cos ^{ 2 }{ x }  }  }  }{ \cos ^{ 2 }{ x }  }  \right)

\\ \\ =\frac { \cos { x }  }{ \sin { x }  } \cdot \frac { \sin ^{ 2 }{ x\left( 1-\cos ^{ 2 }{ x }  \right)  }  }{ \cos ^{ 2 }{ x }  } \\ \\ =\frac { \cos { x }  }{ \sin { x }  } \cdot \frac { \sin ^{ 2 }{ x\cdot \sin ^{ 2 }{ x }  }  }{ \cos ^{ 2 }{ x }  } \\ \\ =\frac { \cos { x } \sin ^{ 4 }{ x }  }{ \sin { x\cos ^{ 2 }{ x }  }  } \\ \\ =\frac { \sin ^{ 3 }{ x }  }{ \cos { x }  }

\\ \\ =\sin ^{ 2 }{ x } \cdot \frac { \sin { x }  }{ \cos { x }  } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \frac { \cos { x }  }{ \sin { x }  }  } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \cot { x }  } \\ \\ =\frac { \sin ^{ 2 }{ x }  }{ \cot { x }  } \\ \\ =RHS
8 0
2 years ago
Can someone help me with this? I will mark you as brainliest
Tresset [83]

Answer:

1372$

Step-by-step explanation:

the  price =15600+20/100*15600=15600*120/100=18720

18720-5000=13720 $

13720:10=1372 $

8 0
3 years ago
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