Question

Please help. I’ll mark you as brainliest if correct!

Answer 1

Answer:

a= -48

b=0

Step-by-step explanation:

$\sqrt[]{-6} = i\sqrt{6}$

$\sqrt{-384} =i\sqrt{384}$

$(i\sqrt{6} )(i\sqrt{384} )$

$i^{2} \sqrt{2304}$

(-1)(48) = -48

a + bi

a= -48

b= 0

Answer 2

Answer:

$\sqrt{-6} \sqrt{-384}=\sqrt{(-6)(-384)}=\sqrt{2304}=48\\ a=48\\b=0$

or

$a=-48\\b=0$

both solutions are correct because root square has two solutions, one positive and one negative.