Answer:
Assuming order does not matter, the probability of selecting all midsize cars is 0.000277373, or
.
Step-by-step explanation:
First, we must find the n(Total arrangements of selections)=(8+15)C6
n(Total arrangements of selections)=23C6
n(Total arrangements of selections)=100,947
Second, we must find the n(Arrangements where all are midsize cars)=8C6
n(Arrangements where all are midsize cars)=28
To find the probability of selecting all midsize cars, we divide the n(Arrangements where all are midsize cars) by the n(Total arrangements of selections):
P(All midsize cars)= ![\frac{28}{100,947}](https://tex.z-dn.net/?f=%5Cfrac%7B28%7D%7B100%2C947%7D)
P(All midsize cars)=
=0.000277373.
Answer:
x^2+4x-5
Step-by-step explanation:
(x+2)(x+2)= x^2+2x+2x+4 simplify
x^2+4x+4=-9 add 9 to other side
x^2+4x-5
Answer:
x5
Step-by-step explanation:
Answer:
First 7 multiples of 9 are:
9,18,27,36,45,54,63. = 36. Hope this helps :3
Answer: Choice C. ![3\sqrt{17}](https://tex.z-dn.net/?f=3%5Csqrt%7B17%7D)
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Work Shown:
![d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(12-15)^2 + (-21-(-9))^2}\\\\d = \sqrt{(12-15)^2 + (-21+9)^2}\\\\d = \sqrt{(-3)^2 + (-12)^2}\\\\d = \sqrt{9 + 144}\\\\d = \sqrt{153}\\\\d = \sqrt{9*17}\\\\d = \sqrt{9}*\sqrt{17}\\\\d = 3\sqrt{17}\\\\d \approx 12.3693169\\\\](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_1%20-%20x_2%29%5E2%20%2B%20%28y_1%20-%20y_2%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%2812-15%29%5E2%20%2B%20%28-21-%28-9%29%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%2812-15%29%5E2%20%2B%20%28-21%2B9%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%28-3%29%5E2%20%2B%20%28-12%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B9%20%2B%20144%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B153%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B9%2A17%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B9%7D%2A%5Csqrt%7B17%7D%5C%5C%5C%5Cd%20%3D%203%5Csqrt%7B17%7D%5C%5C%5C%5Cd%20%5Capprox%2012.3693169%5C%5C%5C%5C)
I used the distance formula for those steps above.
The two points were (x1,y1) = (12,-21) and (x2,y2) = (15,-9) but you could swap the order.
As an alternative route, you can plot the two points on the same xy grid. Then form a right triangle such that the hypotenuse is between the two points mentioned. The pythagorean theorem should lead you to the same answer as above. In fact, the distance formula is basically a modified version of the pythagorean theorem.